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Alex Ar [27]
2 years ago
6

What is the power of a 650N force that moves an object 75cm in 0.63s?​

Physics
1 answer:
Ratling [72]2 years ago
5 0

Answer:

<u>Power</u><u> </u><u>is</u><u> </u><u>7</u><u>7</u><u>3</u><u>.</u><u>8</u><u> </u><u>watts</u>

Explanation:

{ \rm{power =  \frac{force \times distance}{time} }} \\  \\ { \rm{power =  \frac{650 \times 0.75}{0.63} }} \\  \\ { \rm{power = 773.8 \: watts}}

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I WILL MARK YOU IF YOU HELP
sertanlavr [38]
F=ma
11.6=3.8*a
a=11.6/3.8
a=3.05m/s
6 0
2 years ago
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15) On a cold day, you take in 4.2 L (i.e., 4.2 x 10-3 m3) of air into your lungs at a temperature of 0°C. If you hold your brea
Rudiy27

Answer:

4.8L ( i.e 4.8 x 10^-3 m3)

Explanation:

Step 1:

Data obtained from the question.

Initial volume (V1) = 4.2L

Initial temperature (T1) = 0°C

Final temperature (T2) = 37°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 0°C = 0°C + 273 = 273K

T2 = 37°C = 37°C + 273 = 310K

Step 3:

Determination of the final volume.

Since the pressure is constant,

Charles' Law equation will be applied as shown below:

V1 /T1 = V2/T2

4.2/273 = V2 /310

Cross multiply to express in linear form

273 x V2 = 4.2 x 310

Divide both side by 273

V2 = (4.2 x 310)/273

V2 = 4.8L ( i.e 4.8 x 10^-3 m3)

Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)

3 0
3 years ago
A car, traveling at , encounters a dip in the road. The radius of curvature at the bottom of the dip is . Each of the car’s four
labwork [276]

Answer:

spring deflection is  x = (v2 / R + g) m / 4

Explanation:

We will solve this problem with Newton's second law. Let's analyze the situation the car goes down a road and finds a dip (hollow) that we will assume that it has a circular shape in the lower part has the car weight, elastic force and a centripetal acceleration

 

Let's write the equations on the Y axis of this description

       Fe - W = m a_{c}

Where Fe is elastic force, W the weight and a_{c}  the centripetal acceleration. The elastic force equation is

       Fe = - k x

     

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The four is because there are four springs, R is theradio of dip

We can calculate the deflection (x) of the springs

       x = (m v2 / R + mg) / 4

       

       x = (v2 / R + g) m / 4

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3 years ago
When can a theory be modified if a new type of technology allows for new observations that raise new questions?
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Answer:

id say B, but not sure

Explanation:

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