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ANEK [815]
3 years ago
9

I need help ASAP!! I tried every answer but it’s saying there all wrong !

Chemistry
1 answer:
Travka [436]3 years ago
6 0
Mechanical Energy and Thermal Energy

Hope this helps!! :)
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What is the active site of an enzyme?
murzikaleks [220]

Answer:

c. should be it

Explanation:

3 0
4 years ago
Assuming the metals lose all their valence electrons and the nonmetals gain electrons to complete the s-p subshells, which listi
Nataly [62]

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}. When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.

Na^{+} : 1s^{2}2s^{2}2p^{6}

Atomic number of fluorine is 9 and its electronic configuration is 1s^{2}2s^{2}2p^{5}. When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.

F^{-} : 1s^{2}2s^{2}2p^{6}

Atomic number of aluminium is 13 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}. When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.

Al^{3+} : 1s^{2}2s^{2}2p^{6}

Thus, we can conclude that the listing for aluminum is correct.

8 0
3 years ago
Which one is being shown in this picture?
MakcuM [25]

Answer:

B. REFRACTION.

Is shown in fig.

3 0
3 years ago
5) When heated in a flame, the element Indium emits electromagnetic radiation with a distinctive indigo blue
grandymaker [24]

Answer:

\lambda=451nm

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:

E=\frac{hC}{\lambda }

Thus, we solve for the wavelength as shown below:

\lambda=\frac{hC}{ E}

And finally plug in the energy, Planck's constant and speed of light to obtain:

\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm

Regards!

5 0
3 years ago
The solubility of oxygen gas in water at 40 ∘c is 1.0 mmol/l of solution. What is this concentration in units of mole fraction?
juin [17]

The formula for mole fraction is:

mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}    -(1)

The solubility of oxygen gas = 1.0 mmol/L  (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

Density = \frac{mass}{volume}

Mass = 1.0 g/ml\times 1000 mL = 1000 g

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = \frac{1000 g}{18 g/mol} = 55.55 mol

Substituting the values in formula (1):

mole fraction = \frac{0.001}{55.55+0.001}

mole fraction = 1.8\times 10^{-5}

Hence, the mole fraction is 1.8\times 10^{-5}.

7 0
3 years ago
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