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ANEK [815]
3 years ago
9

I need help ASAP!! I tried every answer but it’s saying there all wrong !

Chemistry
1 answer:
Travka [436]3 years ago
6 0
Mechanical Energy and Thermal Energy

Hope this helps!! :)
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The uses of sodium phosphate include clarifying crude sugar, manufacturing paper, removing boiler scale, and washing concrete. W
garri49 [273]

2.4  ×    10⁻² is the pH of a solution

What is the short definition of pH?

  • The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality. Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.
  • In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

Equation representing the i onization of Na₃PO₄ is as fallow

              Na₃PO₄          →                 PO₄³⁻    +  3Na⁺

Concentration of Na₃PO₄ = \frac{26.9 * \frac{1 mol}{164 g} }{1 L} = 0.164 M

Since 1 mol of Na₃PO₄ forms 1 mol of  PO₄³⁻  [  PO₄³⁻  ] = [ Na₃PO₄ ] = 0.164 M

Equation representing the  i onization of HPO²⁻₄ is as fallow

 HPO²⁻₄          →         PO₄³⁻  +    H⁺

Acidionization constant Ka₃ of   HPO²⁻₄  = 4. 17 ×  10⁻¹³

Baseionization constant  Kb₃ of  PO₄³⁻ = Ka₃/ Kb₃

                              = 1 .0  ×  10⁻¹⁴/  4. 17 ×  10⁻¹³  = 2.4  ×    10⁻²

Learn more about pH

brainly.com/question/15289741

#SPJ4

4 0
2 years ago
Which equation represents a chemical equilibrium? * 10 points NH₃(l) ⇌ NH₃(g) N₂(l) ⇌ N₂(g) 2NO₂(g) ⇌ N₂O₄(g) CO₂(s) ⇌CO₂(g)
Vlad [161]

Answer:

(5)

Explanation:

I am always right

6 0
3 years ago
a solution has a volume of 2.0L and contains 36.0 g of glucose. If the molar mass of glucose is 180 g/mol, what is the morality
lilavasa [31]
Find moles: 
<span>36.0 g of glucose divided by 180 g/mol = 0.200 moles of glucose </span>


<span>find molarity: </span>
<span>0.200 moles of glucose / 2 litres = 0.100 Molar solution </span>
3 0
3 years ago
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
3 years ago
What is the electron configuration of a chlorine ion in a compound of BeCl2?
mestny [16]
The  electronic  configuration  of  a   chlorine ion  in BeCl2  compound is

[2.8.8]^-  (answer  B)

chlorine  atom  gain  on electron form Be to  form  chloride ions
chlorine  atom  has  a  electronic   configuration of  2.8.7   and  it  gains one  electron  to  form  chloride ion  with  2.8.8  electronic  configuration
8 0
3 years ago
Read 2 more answers
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