All categories

3 years ago

3. Which muscle tissue lacks striations?

Chemistry

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

Answer:

your answer is b and hope ur help and mark me brainlist

You might be interested in

Number 1 please fast answer

Natasha2012 [34]

Answer:

I will give you 5

Explanation:

color chage, formation of a precipitate, formation of a gas, odor change, temperature change. are all signs of a chemical reaction

3 0

3 years ago

Read 2 more answers

In the following equation:

Luda [366]

Answer:

FeCl₃

Explanation:

4FeCl₃ + 3O₂ => 2Fe₂O₃+ 6Cl₂

Given => 7moles 9moles

A simple way to determine which reagent is the limiting reactant is to convert all given data to moles then divide by the respective coefficients of the balanced equation. The smaller value will be the limiting reactant.

4FeCl₃ + 3O₂ => 2Fe₂O₃+ 6Cl₂

Given => 7/4 = 1.75* 9/3 = 3

*Smaller value => FeCl₃ is limiting reactant.

NOTE: However, when working problems, one must use original mole values given.

7 0

3 years ago

Based on the molar masses. how can you tell that an equation is balanced

harkovskaia [24]

You can tell if each side of the equation has the same molar mass.

3 0

3 years ago

When fluorine gas combines with water vapor, the following reactions occurs.

jonny [76]

Hello!

The Chemical reaction is the following:

2F₂(g) + 2 H₂O(g) → O₂(g) + 4HF(g)

If we assume that all the gases are ideal gases, we can describe the coefficients of this reaction as Volume rather than moles, so we can apply the following equations:

$2 L F_2* \frac{2 L H_2O}{2 L F_2}=2 L H_2O \\ \\ 2 L F_2* \frac{1 mol O_2}{2 L F_2}=1 mol O_2 \\ \\ 2 L F_2* \frac{4 mol HF}{2 mol F_2}= 4 mol HF$

So, 2 L of Water Vapor reacts with the fluorine; and 1 L of Oxygen and 4 L of Hydrogen Fluoride are produced.

Have a nice day!

6 0

3 years ago

Measurements show that unknown compound has the following composition: element mass 38.7 % calcium, 19.9 % phosphorus and 41.2 %

Mademuasel [1]

Answer:

D) empirical formula is: C₃P₂O₈

Explanation:

Given:

Mass % Calcium (Ca) = 38.7%

Mass % Phosphorus (P) = 19.9%

Mass % oxygen (O) = 41.2 %

This implies that for a 100 g sample of the unknown compound:

Mass Ca = 38.7 g

Mass P = 19.9 g

Mass O = 41.2 g

Step 1: Calculate the moles of Ca, P, O

Atomic mass Ca = 40.08 g/mol

Atomic mass P = 30.97 g/mol

Atomic mass O = 16.00 g/mol

$Moles\ Ca = \frac{38.7g}{40.08g/mol} =0.966\ mol\\\\Moles\ P = \frac{19.9g}{30.97g/mol} =0.643\ mol\\\\Moles\ O = \frac{41.2g}{16.00g/mol} =2.58\ mol$

Step 2: Calculate the molar ratio

$C = \frac{0.966}{0.643} =1.50\\\\P = \frac{0.643}{0.643} = 1.00\\\\O = \frac{2.58}{0.643} =4.00$

Step 3: Calculate the closest whole number ratio

C: P: O = 1.50 : 1.00 : 4.00

C : P : O = 3:2:8

Therefore, the empirical formula is: C₃P₂O₈

7 0

3 years ago