The answer is 4.9 moles.
Solution:
Using the equation for boiling point elevation Δt,
Δt = i Kb m
we can rearrange the expression to solve for the molality m of the solution:
m = Δt / i Kb
Since we know that pure water boils at 100 °C, and the Ebullioscopic constant Kb for water is 0.512 °C·kg/mol,
m = (105°C - 100°C) / (2 * 0.512 °C·kg/mol)
= 4.883 mol/kg
From the molality m of the solution of salt added in a kilogram of water, we can now find the number of moles of salt:
m = number of moles / 1.0kg
number of moles = m*1.0kg
= (4.883 mol/kg) * (1.0kg)
= 4.9 moles
It’s x200 plus 300 that’s why it is that answer
First, determine the number of moles of gold.
Number of moles = 
Given mass of gold =
Molar mass of gold = 196.97 g/mol
Put the values,
Number of moles of gold = 
= 
or 
Now, molarity = 
Put the values, volume of ocean =
Molarity = 
= 
Thus, average molar concentration =
The rate in m/s is 5.2 * 10^-4 m/s.
<h3>What is the rate in m/s?</h3>
We know that the speed is given as the ratio of the distance covered to the time taken. In this case, we have been told that the rate at which the tide rises is 6.08 ft per hour. We would now need to convert the rate from 6.08 ft per hour to m/s.
Now;
We know that;
1 foot/hour = 8.5 * 10^-5 m/s
6.08 ft per hour = 6.08 ft per hour * 8.5 * 10^-5 m/s/1 foot/hour
= 5.2 * 10^-4 m/s
Learn more about speed:brainly.com/question/28224010
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The answer is B. because it starts at Conifer Seeds and ends at Northern goshawks.
