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2 years ago

How many chloride ions are in a 220 grams of calcium chloride?

Chemistry

1 answer:

steposvetlana [31]2 years ago

3 0

Answer: Hello, There! Your Answer is Below

2.4 x 1024 ions

Explanation:

220 g of CaCl₂ = X moles

Solving for X,

X = (220 g × 1 mol) ÷ 110.98 g

X = 1.98 moles

As,

1 mole contained = 1.20 × 10²⁴ Cl⁻ Ions

Then,

1.98 mole will contain = X Cl⁻ Ions

Solving for X,

X = (1.98 mol × 1.20 × 10²⁴ Ions) ÷ 1mol

X = 2.38 × 10²⁴ Cl⁻ Ions

Hope this Helps!

Have a great DAy!

`August~

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KatRina [158]

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3 years ago

What ending is given for a compound that contains two elements and oxygen?

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The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be

Stels [109]

Explanation:

1) Initial mass of the Cesium-137= $N_o$ = 180 mg

Mass of Cesium after time t = N

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

Half life of the cesium-137 = $t_{1/2}=30 years[p/tex]where,
[tex]N_o$ = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the isotope

$\lambda$ = rate constant

$N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$N=180mg\times e^{-\frac{0.693}{30 years}\times t}$

Mass that remains after t years.

$N=180 mg\times e^{0.0231 year^{-1}\times t}$

Therefore, the parent isotope remain after one half life will be, 100 grams.

t = 70 years

$N_o=180 mg$

$t_{1/2}= 30 yeras$

$N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}$

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

$N_o=180 mg$

$t_{1/2}= 30 yeras$

N = 1 mg

t = ?

$1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}$

$\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t$

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

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3 years ago

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erastovalidia [21]

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3 years ago

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