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2 years ago

How many chloride ions are in a 220 grams of calcium chloride?

Chemistry

1 answer:

steposvetlana [31]2 years ago

3 0

Answer: Hello, There! Your Answer is Below

2.4 x 1024 ions

Explanation:

220 g of CaCl₂ = X moles

Solving for X,

X = (220 g × 1 mol) ÷ 110.98 g

X = 1.98 moles

As,

1 mole contained = 1.20 × 10²⁴ Cl⁻ Ions

Then,

1.98 mole will contain = X Cl⁻ Ions

Solving for X,

X = (1.98 mol × 1.20 × 10²⁴ Ions) ÷ 1mol

X = 2.38 × 10²⁴ Cl⁻ Ions

Hope this Helps!

Have a great DAy!

`August~

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Answer:

Answer: A) .346 M

Explanation:

Given:

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1) Convert mL to L

450 mL = .45 L

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Answer:Hence, the bond length in HCl is 125 pm.

Explanation:

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Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.

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By titration, it is found that 31.7 mL of 0.145 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentrati

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Answer:

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Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above, the following data were obtained:

Mole ratio of the acid, HCl (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This includes:

Volume of the base, NaOH (Vb) = 31.7 mL Molarity of the base, NaOH (Mb) = 0.145 M

Volume of the acid, HCl (Va) = 25.0 mL

Molarity of the acid, HCl (Ma) =?

Finally, we shall determine the molarity of the acid (HCl) as shown below:

MaVa /MbVb = nA/nB

Ma × 25 / 0.145 × 31.7 = 1

Cross multiply

Ma × 25 = 0.145 × 31.7

Ma × 25 = 4.5965

Divide both side by 25

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