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ZanzabumX [31]
3 years ago
12

Using a meter stick and a ruler with millimeter and centimeter gradations, measure the following objects and record their measur

ements. Select the correct measurement unit for each. Your teacher will check your answers.
Object Measurement
file card ____________
height of a student desk ____________
height and width of notebook paper ______, ______
height and width of nearest door ______, ______
your own height ____________
length of your foot ____________
width of a quarter ____________
length of a pencil ____________
length of a toothpick ____________
distance from floor to ceiling ____________





















PLS HELP ME
Chemistry
1 answer:
Troyanec [42]3 years ago
4 0

Explanation:

you basically just need to measure things with a ruler and write the measurment of the thing in the blank space

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Selected properties of antimony (Sb) and iodine (I) are listed in the table below. Element Atomic radius (pm) First ionization e
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Let us check each statement one by one

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4 years ago
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5 0
3 years ago
Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
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