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ZanzabumX [31]
3 years ago
12

Using a meter stick and a ruler with millimeter and centimeter gradations, measure the following objects and record their measur

ements. Select the correct measurement unit for each. Your teacher will check your answers.
Object Measurement
file card ____________
height of a student desk ____________
height and width of notebook paper ______, ______
height and width of nearest door ______, ______
your own height ____________
length of your foot ____________
width of a quarter ____________
length of a pencil ____________
length of a toothpick ____________
distance from floor to ceiling ____________





















PLS HELP ME
Chemistry
1 answer:
Troyanec [42]3 years ago
4 0

Explanation:

you basically just need to measure things with a ruler and write the measurment of the thing in the blank space

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What distinguishes a substance from a mixture?
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A mixture consists of numerous substances, whereas a substance does not consist of mixtures, but rather of compounds. Mixtures can be separated physically, while substances cannot.
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3 years ago
Calculate the number of kg in 7.66 x 10-5 Gigagrams.
bonufazy [111]

Answer:

76,6 kg

Explanation:

A kg it's equal to 1x10^3 grams

A Gigagrams it's equal to 1x10^9 grams

Knowing this, a kg it's equal to 1x10^6 gigagrams

7,66*10^{-5}[gigagram]*\frac{1*10^6 [kg]}{1 [gigagram]}= 76.6 [kg]

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Why do different solvents affect adsorbate-surface interactions?
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2 years ago
How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

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