The answer is:
B. <span>X: Work is done to the system and temperature increases.
Y: Work is done by the system and temperature decreases.</span>
You are exerting 100N. Since there’s no NET force, then there must be exactly 100N pushing exactly back on your 100N to cancel it to exactly zero. Newton's first law states that whether a body is at rest or travelling in a straight line at a constant speed, it will remain at rest or continue to move in a straight line at a constant speed unless acted upon by a force.
The air resistance on the feather would be the correct answer.
Answer
given,
mass of satellite = 545 Kg
R = 6.4 x 10⁶ m
H = 2 x 6.4 x 10⁶ m
Mass of earth = 5.972 x 10²⁴ Kg
height above earth is equal to earth's mean radius
a) satellite's orbital velocity
centripetal force acting on satellite = ![\dfrac{mv^2}{r}](https://tex.z-dn.net/?f=%5Cdfrac%7Bmv%5E2%7D%7Br%7D)
gravitational force = ![\dfrac{GMm}{r^2}](https://tex.z-dn.net/?f=%5Cdfrac%7BGMm%7D%7Br%5E2%7D)
equating both the above equation
![\dfrac{mv^2}{r} = \dfrac{GMm}{r^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bmv%5E2%7D%7Br%7D%20%3D%20%5Cdfrac%7BGMm%7D%7Br%5E2%7D)
![v = \sqrt{\dfrac{GM}{r}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cdfrac%7BGM%7D%7Br%7D%7D)
![v = \sqrt{\dfrac{6.67 \times 10^{-11}\times 5.972 \times 10^{24}}{2 \times 6.4 \times 10^6}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cdfrac%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%5Ctimes%205.972%20%5Ctimes%2010%5E%7B24%7D%7D%7B2%20%5Ctimes%206.4%20%5Ctimes%2010%5E6%7D%7D)
v = 5578.5 m/s
b) ![T= \dfrac{2\pi\ r}{v}](https://tex.z-dn.net/?f=T%3D%20%5Cdfrac%7B2%5Cpi%5C%20r%7D%7Bv%7D)
![T= \dfrac{2\pi\times 2\times 6.4 \times 10^6}{5578.5}](https://tex.z-dn.net/?f=T%3D%20%5Cdfrac%7B2%5Cpi%5Ctimes%202%5Ctimes%206.4%20%5Ctimes%2010%5E6%7D%7B5578.5%7D)
![T= \dfrac{2\pi\times 2\times 6.4 \times 10^6}{5578.5}](https://tex.z-dn.net/?f=T%3D%20%5Cdfrac%7B2%5Cpi%5Ctimes%202%5Ctimes%206.4%20%5Ctimes%2010%5E6%7D%7B5578.5%7D)
T = 14416.92 s
![T = \dfrac{14416.92}{3600}\ hr](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B14416.92%7D%7B3600%7D%5C%20hr)
T = 4 hr
c) gravitational force acting
![F = \dfrac{GMm}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7BGMm%7D%7Br%5E2%7D)
![F = \dfrac{6.67 \times 10^{-11}\times 545 \times 5.972 \times 10^{24} }{(6.46 \times 10^6)^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%5Ctimes%20545%20%5Ctimes%205.972%20%5Ctimes%2010%5E%7B24%7D%20%7D%7B%286.46%20%5Ctimes%2010%5E6%29%5E2%7D)
F = 5202 N
Answer:
The correct answer is All of the above.
Explanation: