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Misha Larkins [42]
3 years ago
13

A racing car can complete a 900 m long lap in 15 s. What is the speed of the car?

Physics
2 answers:
GREYUIT [131]3 years ago
8 0

Answer:

The speed of the car is 60 m/s.

Explanation:

It is given that,

Distance covered by the racing car, d = 900 m

Time taken by the car, t = 15 s

Let v is the speed of the car. The speed of any object is equal to the distance covered divided by total time taken as :

v=\dfrac{d}{t}

v=\dfrac{900\ m}{15\ s}

v = 60 m/s

So, the speed of the car is 60 m/s. Hence, this is the required solution.

Gemiola [76]3 years ago
4 0

60 is the speed of the car

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A block of mass m = 1.00 kg is attached to a spring of force constant k = 500 N/m. The block is pulled to a position xi= 5.00 cm
8_murik_8 [283]

Answer:

The speed of the block is 4.96 m/s.

Explanation:

Given that.

Mass of block = 1.00 kg

Spring constant = 500 N/m

Position x_{i}=5.00\ cm

Coefficient of friction = 0.350

(A). We need to calculate the speed the block has as it passes through equilibrium if the horizontal surface is friction less

Using formula of kinetic energy and potential energy

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2-\mu mgx

Put the value into the formula

\dfrac{1}{2}\times1.00\times v^2=\dfrac{1}{2}\times500\times(5.00\times10^{-2})-0.350\times1.00\times9.8\times5.00\times10^{-2}

v^2=\dfrac{2\times12.3285}{1.00}

v^2=24.657

v=4.96\ m/s

Hence, The speed of the block is 4.96 m/s.

6 0
3 years ago
A guitarist finds that the pitch of one of her strings is slightly flat—the frequency is a bit too low. Should she increase or d
Yuri [45]

Answer:

The guitarist should increase the tension of the string.

Explanation:

The frequency of a vibrating string is determined by fn=(n/(2L))√T/μ. So if the tension in the string increased, the rate at which it vibrates (the frequency) will also increase.

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6 0
3 years ago
What are the characteristics of low energy waves?
Leokris [45]
I think the correct answer from the choices presented above is the first option. The characteristics of low energy waves are <span>long wavelengths and low frequencies. Energy is established to be indirectly proportional to wavelengths and frequencies.</span>
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Assume that the radius ????r of a sphere is expanding at a rate of 70 cm/min.70 cm/min. The volume of a sphere is ????=43???????
rodikova [14]

Answer:

the rate of change in volume with time is 280πr² cm³/min

Explanation:

Data provided in the question:

Radius of the sphere as 'r'

\frac{d\textup{r}}{\textup{dt}}  = 70 cm/min

Volume of the sphere, V = \frac{\textup{4}}{\textup{3}}\pi r^3

Surface area of the sphere as 4πr²

Now,

Rate of change in volume with time, \frac{d\textup{V}}{\textup{dt}}

 = \frac{d(\frac{\textup{4}}{\textup{3}}\pi r^3)}{dt}

= 3\times\frac{\textup{4}}{\textup{3}}\pi r^2}\times\frac{dr}{dt}

Substituting the value of \frac{dr}{dt}

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= 280πr² cm³/min

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Answer:

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