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irina [24]
3 years ago
10

What must a magnet always have?

Physics
2 answers:
Anna007 [38]3 years ago
8 0

Answer:

Every magnet has both a North and a South pole. When you place the North pole of one magnet near the South pole of another magnet, they are attracted to one another. When you place like poles of two magnets near each other (North to North or South to South), they will repel each other.

ivann1987 [24]3 years ago
4 0

Answer:

All magnets, regardless of their shape or application, must have two poles, the north pole (N) and the south pole (S), which are called magnetic poles.

Explanation:

Magnets are ferromagnetic materials that have the property of attracting or repelling other magnets. In addition, it is characteristic for materials of this nature (ferromagnetic) to be strongly magnetized in the presence of a magnetic field.

All magnets, regardless of their shape or application, must have two poles, the north pole (N) and the south pole (S), which are called magnetic poles. Another important characteristic of magnets is the inseparability of the magnetic poles, that is, it is not possible to find a magnet with only the north pole or only with the south pole. Thus, when a magnet is broken, it will give rise to two new magnets and the polarity of these new magnets will depend on the way in which it partitioned.

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A loop of wire is carrying current of 2 A . The radius of the loop is 0.4 m. What is the magnetic field at a distance 0.09 m alo
HACTEHA [7]

Answer:

B=2.91\ \mu T

Explanation:

Given that,

The current in the loop, I = 2 A

The radius of the loop, r = 0.4 m

We need to find the magnetic field at a distance 0.09 m along the axis and above the center of the loop. The formula for the magnetic field at some distance is given as follows :

B=\dfrac{\mu_o}{4\pi }\dfrac{2\pi r^2 I}{(r^2+d^2)^{3/2}}

Put all the values,

B=10^{-7}\times \dfrac{2\pi \times 0.4^2 \times 2}{(0.4^2+0.09^2)^{3/2}}\\\\=2.91\times 10^{-6}\ T\\\\or\\\\B=2.91\ \mu T

So, the required magnetic field is equal to 2.91\ \mu T.

3 0
3 years ago
Suppose you wish to construct a motor that produces a maximum torque whose magnitude is 1.7 × 10-2 N·m. The coil of the motor ha
Len [333]

Answer:

86 turns

Explanation:

Parameters given:

Magnetic torque, τ = 1.7 * 10^(-2) Nm

Area of coil, A = 9 * 10^(-4) m²

Current in coil, I = 1.1 A

Magnetic field, B = 0.2 T

The magnetic toque is given mathematically as:

τ = N * I * A * B

Where N = number of turns

To find the number of turns, we make N subject of formula:

N = τ/(I * A * B)

Therefore:

N = (1.7 * 10^(-2)) / (1.1 * 9 * 10^(-4) * 0.2)

N = 85.85 = 86 turns (whole number)

The number of turns must be 86.

3 0
4 years ago
The amount of space between two points is measure in unit?
Andreas93 [3]

Answer:

meters

Explanation:

I'm not positive if this is correct, your teacher may be looking for a broader answer so possibly just 'distance'. Hope this helps! <3

3 0
3 years ago
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The best possible Answer is c
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3 years ago
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the answer is most likely likely to be 2

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