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irina [24]
3 years ago
10

What must a magnet always have?

Physics
2 answers:
Anna007 [38]3 years ago
8 0

Answer:

Every magnet has both a North and a South pole. When you place the North pole of one magnet near the South pole of another magnet, they are attracted to one another. When you place like poles of two magnets near each other (North to North or South to South), they will repel each other.

ivann1987 [24]3 years ago
4 0

Answer:

All magnets, regardless of their shape or application, must have two poles, the north pole (N) and the south pole (S), which are called magnetic poles.

Explanation:

Magnets are ferromagnetic materials that have the property of attracting or repelling other magnets. In addition, it is characteristic for materials of this nature (ferromagnetic) to be strongly magnetized in the presence of a magnetic field.

All magnets, regardless of their shape or application, must have two poles, the north pole (N) and the south pole (S), which are called magnetic poles. Another important characteristic of magnets is the inseparability of the magnetic poles, that is, it is not possible to find a magnet with only the north pole or only with the south pole. Thus, when a magnet is broken, it will give rise to two new magnets and the polarity of these new magnets will depend on the way in which it partitioned.

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Puck 1 is moving 10 m/s to the left and puck 2 is moving 8 m/s to the right. They have the same mass, m.
Julli [10]

Answer:

(a) the total momentum of the system before the collision = -2m kg.m/s.

(b) the total momentum of the system after the collision = -2m kg.m/s.

(c) puck 1's velocity after the collision in component form = (5.44 i, 2.54 j)

Explanation:

Given;

mass of Puck 1 , = m

mass of Puck 2, = m (since they have the same mass m)

initial velocity of Puck 1, u₁ = 10 m/s to the left

initial velocity of Puck 2, u₂  = 8 m/s to the right

Let the rightward direction be positive direction

Let the leftward direction be negative direction

(a) the total momentum of the system before the collision;

P₁ = (initial momentum of Pluck 1) + (initial momentum of Pluck 2)

P₁ = (-mu₁) + mu₂

P₁ = mu₂ - mu₁

P₁ = m(u₂ - u₁)

P₁  = m(8 - 10)

P₁  = -2m kg.m/s

(b) the total momentum of the system after the collision;

Based on the principle of conservation of linear momentum, the total momentum before collision is equal to the total momentum after collision.

Thus, the total momentum of the system after the collision is -2m kg.m/s.

(c) puck 1's velocity after the collision in component form

v = (v_x, v_y)\\\\v = (vcos \theta , vsin \theta)\\\\v = (6cos 25^0 , 6sin25^0)\\\\v = (5.44i, 2.54j)m/s

8 0
3 years ago
How to find distance when given mass time and force​
Yuri [45]

Answer:

it is actually very easy & interesting. first write formula of force F=Mass×Acceleration . now see what are the unknowns , mass is known but acceleration is not . so find acceleration, a=velocity/time , but now again we dont know velocity, V= distance/time . subbing in all the values, Force=Mass×(distance/time^2)

Hope it helps if you have any problem feel free to ask.

7 0
3 years ago
The student in item 1 moves the box up a ramp inclined at 12 degrees with the horizontal. If the box starts from rest at the bot
Alik [6]

Answer:

Acceleration up the ramp =  -2.745 m/s^{2}

Explanation:

Given

box is pulled at angle Θ = 25^{o}

Force applied F = 185N

coefficient of friction, μ_{k} = 0.27

mass of the box m = 35 kg

We know that,

acceleration due to gravity g = 9.8 m/s^{2}

horizontal component F_{x} = F cosΘ = 185 * cos25^{o} =167.67

vertical component F_{y} = F sinΘ =185*sin25^{o} = 78.18

Another vertical component is due to gravity F_{g} , force in given by

F_{g} = mg

    = 35 x 9.8

    = 343.35 N

Normal force F_{n} = F_{g}  - F_{y}

                            = 343.35 - 78.18

                            = 265.17 N

Frictional force F_{k} = F_{n} * μ_{k}

                               = 265.17 * 0.27

                               = 71.596 N

To find acceleration, we know that,

force = mass x acceleration

acceleration = \frac{force}{mass}

Here force is the summation of frictional force and horizontal component of the applied force. These force act in opposite directions.

force =  F_{k} - F_{x}

         = 71.596 - 167.67

         = -96.074

acceleration = \frac{-96.074}{35}

                     = -2.745 m/s^{2}

6 0
3 years ago
Oxygen-15 undergoes beta decay. Which particle correctly completes the
Ne4ueva [31]

Answer:

Option C. ⁰₊₁e

Explanation:

From the question given above, the following data were obtained:

¹⁵₈O —> ¹⁵₇N + __

Let the unknown be ʸₓM

Thus, the equation becomes

¹⁵₈O —> ¹⁵₇N + ʸₓM

Next, we shall determine x, y and M. This can be obtained as follow:

8 = 7 + x

Collect like terms

8 – 7 = x

1 = x

x = 1

15 = 15 + y

Collect like terms

15 – 15 = y

0 = y

y = 0

ʸₓM => ⁰₁M => ⁰₊₁e

Therefore,

¹⁵₈O —> ¹⁵₇N + ʸₓM

¹⁵₈O —> ¹⁵₇N + ⁰₊₁e

5 0
3 years ago
Please helppp ! Is my choice right ?
grin007 [14]
Yes you are right because if both of the photons are the same nothing is really happening thereafter c is the correct answer.
6 0
4 years ago
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