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sattari [20]
3 years ago
13

What is the molar mass of an ideal gas if a 0.800 g sample of this gas occupies a volume of 200. mL at 50.0 oC and 720. mm Hg?

Physics
1 answer:
Paladinen [302]3 years ago
7 0
PV=nRT
(720/760)(0.200)=(0.800/x)(0.08206)(323.15)
(0.1894736842)=(0.800/x)(0.08206)(323.15)
.0071451809=(0.800/x)
x=MM=111.9635758 g/mol
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The blackbody emission spectrum of object A peaks in the ultraviolet region of the electromagnetic spectrum at a wavelength of 2
seraphim [82]

Answer:

A) Object A is 3.25 times hotter.

B) Object A radiates 111.6 times more energy per unit of area.

Explanation:

Wiens's law states that there is an inverse relationship between the wavelength in which there is a peak in the emission of a black body and its temperature, mathematically,

\lambda_{peak}= \dfrac{0.0028976}{T},

where T is the temperature in kelvins and, \lambda_{peak} is the wavelenght (in meters) where the emission is in its peak.

From here, if we solve Wien's law for the temperature we get

T=\dfrac{0.0028976}{\lambda_{peak}}.

Now, we can easily compute the temperatures.

For object A:

T_{A}=\dfrac{0.0028976}{200*10^{-9}}

T_{A}=14488K.

For object B:

T_{B}=\dfrac{0.0028976}{650*10^{-9}}

T_{B}=4458K

From this, we get that

T_{A}/T_{B}=3.25,

which means that object A is 3.25 times hotter.

Stefan's Law states that a black body emits thermal radiation with power proportional to the fourth power of its temperature.

This is

E=\sigma T^{4},

where  \sigma=5.67*10^{-8}\ Wm^{-2}K^{-4} is call the Stefan-Boltzmann constant.

From this, power can be easily compute:

E_{A}=(5.67*10^{-8}*(14488)^{4})=2.5*10^{9}W\\E_{B}=(5.67*10^{-8}*(4458)^{4})=22.4*10^{6}}W,

and we can notice that

E_{A}/E_{B}=111.6,

which means that object A radiates 111.6 time more energy per unit of area.

8 0
3 years ago
What is the main difference between the gas water vapor and the liquid water?
Vinil7 [7]
Water vapour has more kinetic energy.

Hope this helps :)
6 0
3 years ago
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an electron and a 0.0320-kg bullet each have a velocity of magnitude 510 m/s, accurate to within 0.0100%. within what lower limi
MArishka [77]

for this we apply, Heisenberg's uncertainty principle.

it states that physical variables like position and momentum, can never simultaneously know both variables at the same moment.

the formula is,

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

by rearranging,

Δx = h / 4π * m(e).Δv

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 / 583.9 X 10 ⁻³¹

Δx = 0.011 X 10⁻³

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.032*10^-31 * 5.10*10^-2

Δx = 6.63*10^-34 /2.05

Δx =3.23 X 10⁻³² m

therefore, we can say that the lower limits are   0.011 X 10⁻³  m for the electron and  3.23 X 10⁻³² m   for the bullet

To know more about bullet problem,

brainly.com/question/21150302

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6 0
1 year ago
According to Lenz's law, an induced current in the direction depicted in the picture would be created when: a. An external downw
LenKa [72]

Answer:

C. An external downward field is created or an external downward field is removed

Explanation:

As we can see that from the attached figure that the induced current would be counter clockwise. So the field occur because of induced current i.e. out of page. This represent that the current is induced in order to rise the flux out of the direction of the page

Therefore because of the external field, the field out of page & flux would be reducing or the external upward field is eliminated

So option C is correct

7 0
3 years ago
How could you increase the number of snowmen destroyed by the sled sliding down the hill? SledAQ1 A. Increase the starting heigh
Dima020 [189]
To increase the number of snowmen destroyed, you would want more energy and all of the above would increase the energy of the system so D.
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3 years ago
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