Answer:
See explanation
Explanation:
In this question, we have to follow the IUPAC rules. Lets analyze each compound:
a. 1-methylbutane
In this compound we have a chain of 5 carbons, so the correct name is <u>Pentane.</u>
b. 1,1,3-trimethylhexane
In this compound, we longest chain is made of 7 carbons, so, we have to use the name "heptane". Carbon one would be the closet one to the methyl group, so the correct name is <u>2,4-dimethylheptane.</u>
c. 5-octyne
In this case, carbon 1 would be the closet one to the triplet bond. With this in mind, the correct name is <u>oct-3-yne.</u>
d. 2-ethyl-1-propanol
In this compound, we longest chain is made of 4 carbons, so, we have to use the name "butane". Carbon one would be the carbon with the "OH" group, so the correct name is <u>2-methylbutan-1-ol.</u>
<u>e. 2.2-dimethyl-3-butanol</u>
In this case, carbon 1 would be the closet one to the "OH". With this in mind, the correct name is <u>3,3-dimethylbutan-2-ol.</u>
See figure 1
I hope it helps!
Strong acid on combining with strong base will always give neutral solutions. Consider the following example for the same
HCl + NaOH ↔ NaCl + H2O
(strong (strong
acid) base)
In above case, the resultant solution is neutral in nature.
On other hand, weak acid will react with strong base to form salt and water. But the solution will be basic in nature. Also, strong acid will react with weak base to form salt and water. But the solution will be acidic in nature
the answer to the question that you have presented us with today is B.
and if you do not like my answer then you will stub your big toe in the next week. thanks