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Kaylis [27]
3 years ago
15

If a very complex closed system has 200 J of energy in it, then the energy converts from 1 form to another to another to another

. How much energy should the system still have at the end?
Chemistry
1 answer:
weqwewe [10]3 years ago
4 0

At the end the energy of the system is the same as 200 J.

<u>Explanation:</u>

It is a closed complex system and it has 200 J of energy.

Here the system is converting from one form to another form and then to another form.

As we know that there is a conservation of energy when one form is converted to another form without losing or gaining energy, whereas it may convert from one form to another form with the energy being conserved.

So after there is a conversion of one form to another form but there is no loss or gain of energy and same energy must be retained.

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liam uses a machine that counts waves on a metal cable. The machine counts 25 waves in 2 seconds. what is the frequency of the w
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Billy the friendly Robot uses 50 N of force to lift a box 2 meters in the air. How much work did Billy perform?
nexus9112 [7]

Answer:

Work done, W = 100 J

Explanation:

We have, Billy the friendly Robot uses 50 N of force to lift a box 2 meters in the air.

It is required to find the work done by Billy.

Work done by an object is given in terms of force and displacement. The formula used to find the work done is given by :

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4 0
3 years ago
What is the percent composition of dinotrogen pentoxide? With work shown please
iris [78.8K]

Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%

7 0
3 years ago
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