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3 years ago

3.5.6 Introduce Yourself, Part 2 please hellllpp it keeps saying the code is wrong

Computers and Technology

1 answer:

dalvyx [7]3 years ago

3 0

Answer:

In Python:

name = "Arthur"

age = "62"

print("Hi! My name is "+name+" and I am "+age+" years old")

Explanation:

Given

See attachment

Required

Write a code to introduce yourself

Initialize name

name = "Arthur"

Initialize age

age = "62"

Print introduction

print("Hi! My name is "+name+" and I am "+age+" years old")

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gavmur [86]

Answer:

def occurencesOfWords(words,freq):

frequency_dictionary={}

matched_frequency_words=[]

for i in range(len(words)):

counter=1

a=words[i].lower()

for j in range(len(words)):

if(i==j):

continue

b=words[j].lower()

if(a==b):

counter+=1

frequency_dictionary[words[i]]=counter

for key in frequency_dictionary:

if(frequency_dictionary[key]==freq):

matched_frequency_words.append(key)

return matched_frequency_words

if __name__=='__main__':

user_input=input()

freq=int(input())

words=user_input.split(" ");

required_words=occurencesOfWords(words,freq)

for s in required_words:

print(s)

Explanation:

Inside the occurencesOfWords function, initialize a frequency_dictionary that is used to store the string and the frequency of that specific string .
matched_frequency_words is an array that is used to store each string whose frequency matches with the provided frequency
Run a nested for loop up to the length of words and inside the nested for loop, skip the iteration if both variables i and j are equal as both strings are at same index.
Increment the counter variable, if two string are equal.
Loop through the frequency_dictionary to get the matching frequency strings .
Finally test the program inside the main function.

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3 years ago

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elixir [45]

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Explanation:

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ipn [44]

Answer:

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Explanation:

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4 years ago