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prohojiy [21]
3 years ago
8

If an element is a semi-conductor, which classification correctly describes it?

Physics
1 answer:
stiks02 [169]3 years ago
8 0

Metal

Explanation:

semiconductors are materials which have a conductivity between conductors (generally metals)

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Why doesnt food have energy
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Food has calories which feeds your bones in your body from eating away your muscles, it doesn’t have “energy” on the other hand pop and drinks do.
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HELP ME ASAP!!!!! A patient in the hospital is undergoing testing. The patient's brain is sending electrical signals to motor ne
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3 years ago
You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th
Luden [163]

Answer:

Explanation:

From your other post, the complete question is:

"You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.

Find the sum of the force on the sled.

Determine the acceleration of the sled .

If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?

"

Given the rope exerting a force of 50 N to the right and the snow exerts a friction force of 30 N to the left, the sum of forces

= 50 - 30

= 20N to the right

The mass of sled is 50 kg and force = mass * acceleration.

Acceleration = Force / mass

= 20 / 50 = 0.4 m/s^2 to the right

If the sled has an initial velocity 2m/s to the right, after 5 seconds it will be traveling at initial velocity + acceleration * time

= 2 + 0.4*5

= 4 m/s to the right

3 0
3 years ago
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If the atmospheric pressure in a tank is 23 atmospheres at an altitude of 1,000 feet, the air temperature in the tank is 700F, a
liraira [26]

Answer:

W = 289.70 kg

Explanation:

Given data:

Pressure in tank = 23 atm

Altitude 1000 ft

Air temperature  in tank T = 700 F

Volume of tank = 800 ft^3 = 22.654 m^3

from ideal gas equation we have

PV =n RT

Therefore number of mole inside the tank is

\frac{1}{n} = \frac{RT}{PV}

              = \frac{8.206\times 10^{-5}} 644.261}{23\times 22.654}

               = 1.02\times 10^{-4}

               n = 10^4 mole

we know that 1 mole of air weight is 28.97 g

therefore, tank air weight is W = 10^4\times 28.91 g = 289700 g

               W = 289.70 kg

6 0
3 years ago
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