<h2>
Answer: 1 to 12.
</h2>
<u>The Mercalli seismological scale is a scale of 12 degrees</u>, where 1 is very weak and 12 catastrophic.
This scale owes its name to the Italian physicist Giuseppe Mercalli and was developed to assess the intensity of earthquakes through the effects and damages caused to different structures.
This means the <u>Mercalli scale measures how strong a earthquake has been by </u><u>its consequences and not by its magnitude</u><u>, therefore it is based on </u><u>empirical observations.</u>
Because it doesn't use energy it uses mechanical and kinetic
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
![\Delta U + \Delta K=0](https://tex.z-dn.net/?f=%5CDelta%20U%20%2B%20%5CDelta%20K%3D0)
which means
![\Delta K = - \Delta U](https://tex.z-dn.net/?f=%5CDelta%20K%20%3D%20-%20%5CDelta%20U)
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (
![\Delta V=-1000 V](https://tex.z-dn.net/?f=%5CDelta%20V%3D-1000%20V)
):
![\Delta U = q \Delta V=(1 eV)(-1000 V)=-1000 eV](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20q%20%5CDelta%20V%3D%281%20eV%29%28-1000%20V%29%3D-1000%20eV)
Therefore, the kinetic energy gained by the proton is
![\Delta K = -(-1000 eV)=1000 eV](https://tex.z-dn.net/?f=%5CDelta%20K%20%3D%20-%28-1000%20eV%29%3D1000%20eV)
<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
An intense solar storm COULD disrupt communications and damage the power grid. <em> (A)</em>