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guajiro [1.7K]
3 years ago
14

Please answer as soon as possible if you can

Chemistry
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

Second one

Explanation:

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Convert the speed of light, 3.0 x 10^8 m/s, into mi/hr. (1610 m = 1 mi). Could you please explain step by step thank you!
jenyasd209 [6]

Answer:

v=6.7\times 10^9\ mi/hr

Explanation:

Given that,

The speed of light is 3×10⁸ m/s

We need to convert it into mi/hr.

Since, 1 mile = 1610 m

1 hour = 3600 s

So,

v=3\times 10^8\ \dfrac{m}{s}\\\\=3\times 10^8\ \dfrac{\dfrac{1}{1610}\ \text{miles}}{\dfrac{1}{3600}\ s}\\\\=6.7\times 10^9\ mi/hr

So, the required speed of light is 6.7\times 10^9\ mi/hr.

8 0
3 years ago
What kind of change occurs when I’ve becomes liquid water
gregori [183]

Answer:

Its a physical

theres no chemical properties involved.

Explanation:

Brainliest please

6 0
3 years ago
You are to write a poem or song about the planets and the information you submit have to be true about each planet.
snow_tiger [21]
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7 0
3 years ago
Read 3 more answers
In what area of the titration curve for phosphoric acid (h3po4) is the molecule fully deprotonated?
Arada [10]

The titration curve should have flat regions centered around each of the

three halfway points (buffer zones) and sharp increases in pH around the

equivalence points.

Initial pH

This is determined by the most acidic of the Ka values and the initial

concentration of the acid. (Same as a monoprotic acid)

Half-way points

At each halfway point, the pH = pKa of the group you are titrating. At this point in

the titration curve, we are in a buffering region, and the curve will be relatively

flat.

Equivalence points

At each equivalence point, the pH is the average of the pKa values above and

below. At the last equivalence point (the endpoint), the pH is determined by the

Kb of the conjugate base of the weakest acid.

Plotting the titration of 100 mL of 0.10 M phosphoric acid with 1.0 M NaOH.

H3PO4 + H2O  H2PO4

-

+ H3O+

Ka1 = 7.5 x 10-3

H2PO4

-

+ H2O  HPO4

2- + H3O+

Ka2 = 6.2 x 10-8

HPO4

2- + H2O  PO4

3- + H3O+

Ka3 = 4.2 x 10-13

Plot these points and connect them to determine the titration curve of phosphoric acid. The curve should be relatively flat around each of the halfway points when we are in a buffering region.

The titration curve should have flat regions centered around each of the

three halfway points (buffer zones) and sharp increases in pH around the

equivalence points.

For more information on the titration curve click on the link below:

brainly.com/question/3130161

#SPJ4

4 0
2 years ago
For the reaction 2Na + Cl2 → 2NaCl, how many grams of chlorine gas are required to react completely with 57.5 mol of sodium?
Step2247 [10]

Answer:

1019.27 g.

Explanation:

  • For the balanced reaction:

<em>2Na + Cl₂ → 2NaCl,</em>

It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.

  • Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:

2 moles of Na need → 1 mol of Cl₂, from the stichiometry.

57.5 moles of Na need → ??? mol of Cl₂.

<em>∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na =</em> (1 mol)(57.5 mol)/((2 mol) <em>= 28.75 mol.</em>

<em>∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) =</em> (28.75 mol)(35.453 g/mol) <em>= 1019.27 g.</em>

4 0
3 years ago
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