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Jobisdone [24]
3 years ago
14

1

Chemistry
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

I believe the answer to be period 3 group 1

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Please answer correctly ...I will mark you brainliest
Valentin [98]

Answer:

Ali will need to either taste test or test the drinks on a ph scale. A neutral drink is water, as neutral has a ph of 7. The ph scale ranges from 1 to 14, going from acidic to basic. So if the drink has a ph less than 7, it is acidic, if its more, its basic.

4 0
3 years ago
Read 2 more answers
For each of the following compounds, identify what type of bonding holds them together.
svet-max [94.6K]

Explanation

NaCl:  Ionic crystal lattice forces

Hg:   Metallic bonding

CO₂:  London dispersion forces

CH₄:  London dispersion forces

Li₂O:  Ionic crystal lattice forces

Ag:  Metallic bonds

Ionic crystal lattice forces are strong electrostatic force of attraction between oppositely charged ions arranged into a crystal lattice of ionic compound. NaCl and Li₂O are ionic compounds

London dispersion forces holds the molecules of carbon dioxide and methane. They are weak attractions found between non-polar (and polar) molecules.

Metallic bonds exists between Mercury and Gold atoms. This is due to sea of electrons present.

4 0
3 years ago
If the half-life of Carbon-14 is 5700 years, how many years would it take a sample to decay from 1 gram to 31.3 mg
andrew-mc [135]

Answer:

28500 years

Explanation:

Applying,

A = A'(2^{x/y})............... Equation 1

Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.

From the question,

Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.

Substitute these values into equation 1

1 = 0.0313(2^{x/5700})

2^{x/5700} = 1/0.0313

2^{x/5700}  = 31.95

2^{x/5700} ≈ 32

2^{x/5700} ≈ 2⁵

Equating the base and solve for x

x/5700 ≈ 5

x ≈ 5×5700

x ≈ 28500 years

3 0
3 years ago
How many grams of pure naoh must be used to prepare 10.0 l of a solution that has a ph of 13? __________g?
padilas [110]

40 g NaOH. You must use 40 g NaOH to prepare 10.0 L of a solution that has a pH of 13.

<em>Step 1</em>. Calculate the pOH of the solution

pOH = 14.00 – pH = 14.00 -13 = 1

<em>Step 2</em>. Calculate the concentration of NaOH

[NaOH] = [OH^(-)] = 10^(-pOH) mol/L = 10^(-1) mol/L = 0.1 mol/L

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 10.0 L solution × (0.1 mol NaOH/1 L solution) = 1 mol NaOH

<em>Step 4</em>. Calculate the mass of NaOH

Mass of NaOH = 1 mol NaOH × (40.00 g NaOH/1 mol NaOH) = 40 g NaOH

8 0
3 years ago
What element has the electron configuration below? *<br><br> please help me
timofeeve [1]

Answer:

Symbol Ar

Group 18

Electron configuration- 1s² 2s² 3p6 3s² 3p6

Explanation:

The 6 is small and will be placed in top but I don't have the option that's why I wrote like that

8 0
2 years ago
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