3 years ago

PLEASE HELP.!

Chemistry

1 answer:

Agata [3.3K]3 years ago

6 0

Answer:

Explanation:

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Which describes the normal boiling point of a substance?

kicyunya [14]

Answer:

I think it's D

Explanation:

I'm so sorry if that's wrong, hope it helps!

6 0

3 years ago

For the reaction, a → b, the rate constant is 0.0208 m-1 sec-1. How long would it take for [a] to decrease from 0.100 to 0.0450

goldfiish [28.3K]

First, assume the order of the given reaction is n, then the rate of reaction i.e. $\frac{dx}{dt}=k\times[A]^{n}$

where, dx is change in concentration of A in small time interval dt and k is rate constant.

According to units of rate constant, the reaction is of second order.

$\frac{1}{[A]_{t}}-\frac{1}{[A]_{o}} = kt$ (second order formula)

Put the values,

$\frac{1}{0.04590 m}-\frac{1}{0.100 m} =0.0208 m^{-1}s^{-1} \times t$

$22.23 m -10 m =0.0208 m^{-1}s^{-1} \times t$

$\frac{12.23 m}{0.0208 m^{-1}s^{-1}} = t$

t= 587.9 s

Hence, time taken is 587.9 s

5 0

3 years ago

Last giveaway! <br> 30 <3

Scorpion4ik [409]

Answer:

Explanation:

Hi hi

8 0

3 years ago

Read 2 more answers

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation

AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ $(P+\frac{n^2 a}{v^2} )(v-nb)=nRT$

or,

⇒ $P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}$

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ $P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}$

$=\frac{(0.467)^2\times 3.49}{(0.245)^2}$

$=73.61-13.05$

$=60.56 \ atm$

8 0

3 years ago

MatroZZZ [7]

The correct answer is Reference Point

7 0

3 years ago