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Stells [14]
3 years ago
10

A space station that does not rotate cannot simulate gravity for its occupants.

Physics
1 answer:
ss7ja [257]3 years ago
5 0

<u>Answers:</u>

1. True: If we want to simulate gravity inside a space station, this must rotate about its axis, creating the artificial gravity environment by the centripetal acceleration.  


2. True: The Centrifugal force is a fictitious force that appears when the movement of a body is described in a rotating reference system, or equivalently the apparent force perceived by a non-inertial observer in a rotating reference system.


This means that a non-inertial observer on a rotating platform feels that there is a "force" acting on him, which prevents him from remaining at rest on the platform unless he applies another force directed towards the axis of rotation


3. True: This is possible because the station axis, which is the center of rotation of the system, has the lowest artificial gravity (tending to zero or null gravity). Therefore, the weight of a body in that place will tend to zero, in other words,<u> will be weightless.</u>


4. False: Only having a floor to walk on, is not enough to feel the gravity if the station is not a <u>rotating system</u>.


5.False: The astronaut will experience the centrifugal force, which is a inertial force that will tend to push her back .


This is because the rotation displaces any object or body  from the interior of the station towards its walls, giving the appearance of a gravitational thrust directed towards the exterior. The "push", or centrifugal force is actually a manifestation of the objects inside the ship attempting to move in a straight line due to inertia.

The walls of the station provide the centripetal force required for objects to move in a circle. Therefore, the gravity felt by the objects is a simple reaction of force of the object on the walls reacting with the centripetal force of the wall on the object, according to Newton's third law of motion.



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Explanation:

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The volume of a cylindrical tin can with a top and a bottom is to be 16π cubic inches. If a minimum amount of tin is to be used
sergiy2304 [10]

Answer:

h = 4 in

Explanation:

GIVEN DATA:

volume of tin= 16 \pi

we know that

volume of cylinder is v = \pi r^2  h

so,

16 \pi = \pi r^2 h

16 = r^2 h

r = \sqrt{\frac{16}{h}}

construct formula for surface area

S = 2\pi r^2 +  2\pi rh

S = \frac{2v}{h} + 2 \sqrt{v \pi h}

minimize the function wrt  h

S' = \frac{2v}{h^2} + \sqrt{\frac{v \pi}{h} =  0

solving for h we have

h = [\frac{4 v}{\pi}]^{1/3}

we kow v = 16 \pi   so

h = 4 in

8 0
3 years ago
If there are 50 people per square kilometer in a city, and the area of the city is 1.5 × 10 square kilometers. What is the total
qaws [65]

Answer:

750 people

Explanation:

From the question,

Number of people in the city = population density×Area of the city

N = D×A.......................... Equagtion 1

Where N = Number of people in the city, D = population density, A = Area of the city.

Given: D = 50 people per square kilometer, A = 1.5×10 square kilometer.

Substitute into equation 1

N = 50(1.5×10)

N = 750 people.

Hence the total number of people in the city is 750 people.

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Which element of variation would not be affected by adding the data value 15 to the data set {3, 5, 6, 8, 9, 10, 13, 14}?
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What would happen if you place 2 Plane Mirrors parallel to each other?
e-lub [12.9K]

Answer:

No image will be observed.

Explanation:

Images that are created by mirrors are virtual images. This virtual image can only be seen by an observer. In this case, an infinite number of images or no image will be created here as both will be reflecting their own images. Light will continuously bounce back and forth reflecting the same image.

6 0
3 years ago
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