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Stells [14]
3 years ago
10

A space station that does not rotate cannot simulate gravity for its occupants.

Physics
1 answer:
ss7ja [257]3 years ago
5 0

<u>Answers:</u>

1. True: If we want to simulate gravity inside a space station, this must rotate about its axis, creating the artificial gravity environment by the centripetal acceleration.  


2. True: The Centrifugal force is a fictitious force that appears when the movement of a body is described in a rotating reference system, or equivalently the apparent force perceived by a non-inertial observer in a rotating reference system.


This means that a non-inertial observer on a rotating platform feels that there is a "force" acting on him, which prevents him from remaining at rest on the platform unless he applies another force directed towards the axis of rotation


3. True: This is possible because the station axis, which is the center of rotation of the system, has the lowest artificial gravity (tending to zero or null gravity). Therefore, the weight of a body in that place will tend to zero, in other words,<u> will be weightless.</u>


4. False: Only having a floor to walk on, is not enough to feel the gravity if the station is not a <u>rotating system</u>.


5.False: The astronaut will experience the centrifugal force, which is a inertial force that will tend to push her back .


This is because the rotation displaces any object or body  from the interior of the station towards its walls, giving the appearance of a gravitational thrust directed towards the exterior. The "push", or centrifugal force is actually a manifestation of the objects inside the ship attempting to move in a straight line due to inertia.

The walls of the station provide the centripetal force required for objects to move in a circle. Therefore, the gravity felt by the objects is a simple reaction of force of the object on the walls reacting with the centripetal force of the wall on the object, according to Newton's third law of motion.



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State the conservation of momentum theorem
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Answer:

The total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

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2 years ago
There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted s
lukranit [14]

Answer:

Option B

a=19 m/s^{2}

Explanation:

Given information

Radius of container, r=12cm=12/100=0.12m

Angular velocity= 2 rev/s, converted to rad/s we multiply by 2π

Angular velocity, \omega=2*2\pi =12.56637061

We know that speed, v=r\omega

Centripetal acceleration, a=\frac {v^{2}}{r} and substituting v=r\omega we obtain that

a=r\omega^{2}

Substituting \omega for 12.56637061  and r for 0.12

a=0.12*(12.56637061)^{2}=18.94964045 m/s^{2}

Rounded off, a=19 m/s^{2}

7 0
3 years ago
How to find a planet’s gravitational field strength using its radius?
grin007 [14]

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

g = \frac{F}{m}

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And F =\frac{GMm}{r^{2} }

Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11}  \times 1}{(6.6 \times 10^{6}) ^{2} }

g = 0.977 \times 10^1= 9.77\ N

So, the gravitational field strength is approximately equal to 10 N.

5 0
3 years ago
Which is true of a mechanical wave?
mario62 [17]
A mechanical wave must have a medium.

Hope this helps,
♥<em>A.W.E.<u>S.W.A.N.</u></em>♥
6 0
3 years ago
Read 2 more answers
A water gun fires 5 squirts per second. The speed of the squirts is 15 m/s.
stira [4]

Answer: 3.75 m

Explanation:

5 squirts in 1 second

So, 1 squirt in 1/5 second which is 0.2 second.

The difference in timing of two consecutive squirt is 0.2 second, so

time (t) = 0.2 s.

speed (s) = 15 m/s

Distance of separation (d) = ?

Now, formula for distance is

d = s × t

d = 15 × 0.2

d = 3.75 m

4 0
3 years ago
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