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mash [69]
3 years ago
5

En un parque de atracciones hay una montaña rusa donde los primeros 140 metros son en línea recta, si desde que el carrito esta

en reposo hasta que llega a los 140 metros se le aplica una aceleración constante de 7.5 m/s, calcular el tiempo...
Physics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

Tiempo, t = 6.11 segundos.

Explanation:

Dados los siguientes datos;

Distancia = 140 m

Aceleración = 7,5 m/s²

Dado que el objeto partió del reposo, su velocidad inicial es igual a 0 m/s.

Para encontrar el tiempo, usaríamos la segunda ecuación de movimiento;

S = ut + ½at²

Dónde;

S representa el desplazamiento o la altura medida en metros.

u representa la velocidad inicial medida en metros por segundo.

t representa el tiempo medido en segundos.

a representa la aceleración medida en metros por segundo cuadrado.

Sustituyendo en la ecuación, tenemos;

140 = 0*t + ½*7.5*t²

140 = 0 + 3.75t²

140 = 3.75t²

Dividiendo ambos lados por 3,75, tenemos;

t² = 140/3.75

t = √37.33

Tiempo, t = 6.11 segundos

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a) The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):

KE = \frac{1}{2}m* v^{2}

It is given:

v = 8.5 m/s

m = 91 kg

So:

KE= \frac{1}{2}*91*8.5^{2} =3,287.4J


b) We can calculate height by using the formula for potential energy (PE):
PE = m*g*h

In this case, h is eight, and PE is the same as KE:
PE = KE = 3,287.4 J

m = 91 kg

g = 9.81 m/s² - gravitational acceleration

h = ? - height


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3,287.4= 91 * 9.81 * h

⇒ h = 3,287.4/(91*9.81) = 3,287.4/892.7 = 3.7 m

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3 years ago
The texture of obsidian is best described as glassy.Why does obsidian contain few or no mineral grains? by the way I put it unde
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3 years ago
Parallel rays of monochromatic light with wavelength 571nm illuminate two identical slits and produce an interference pattern on
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Answer:

8.8\times 10^{-6} W/m^2

Explanation:

We are given that

Wavelength,\lambda=571 nm=571\times 10^{-9} m

1 nm=10^{-9} m

R=75 cm=\frac{75}{100}=0.75 m

1 m=100 cm

d=0.640 mm=0.64\times 10^{-3} m

1 mm=10^{-3} m

a=0.434 mm=0.434\times 10^{-3} m

y=0.830 mm=0.830\times 10^{-3} m

I_0=5.00\times 10^{-4}W/m^2

tan\theta=\frac{y}{R}

\theta=\frac{0.830\times 10^{-3}}{0.75\times 10^{-2}}

\theta=1.1\times 10^{-3}rad

tan\theta\approx \theta

Because \theta is small.

\phi=\frac{2\pi dsin\theta}{\lambda}

\sin\theta\approx \theta,

Therefore

\phi=\frac{2\times\pi\times 0.64\times 10^{-3}\times 1.1\times 10^{-3}}{571\times 10^{-9}}

\phi=7.74 rad

\beta=\frac{2\pi a\theta}{\lambda}

\beta=5.3 rad

I=I_0cos^2(\frac{\phi}{2})(\frac{sin\frac{\beta}{2}}{\frac{\beta}{2}})^2

I=5\times 10^{-4}cos^2(\frac{7.74}{2})(\frac{sin\frac{5.3}{2}}{\frac{5.3}{2}})^2

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3 years ago
Look at the circuit below. What is the voltage between points C and D?
stepan [7]

Option c) 1.5 V

Explanation:

<em>As the circuit is build in series first we will find the current passing through the complete circuit. Current stays the same in each element is the series cirucuit, however, the voltage is different.</em>

Voltage is given by the following formula:

V = IR

<em>Because we have to find current through whole circuit, we will first find resistance of the whole circuit.</em>

Equivalent Resistance R(eq): R1 + R2 = 60 + 60 = 120 ohm

Current passing through whole circuit be:

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Current stays the same in series circuit: I = 0.025 c

Resistance between C and D is, R = 60 ohm

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