En un parque de atracciones hay una montaña rusa donde los primeros 140 metros son en línea recta, si desde que el carrito esta
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Answer:
showm
Explanation:
Consider a dipole having magnetic moment 'm' is placed in magnetic field then the torque exerted by the field on the dipole is
Now to rotate the dipole in the field to its final position the work required to be done is
Minimum energy mB is for the case when m is anti parallel to B.
Minimum energy -mB is for the case when m is parallel to B.
Answer:
The coefficient of friction present between the roadway and the wheels of the truck is <u>0.833</u>.
Explanation:
Given:
Radius of the curve (R) = 150 m
Maximum speed of truck (v) = 35.5 m/s
Let the coefficient of friction between the roadway and the wheels of the truck be "μ".
As the truck is moving around a circular curve. So, the force acting on it is centripetal force which acts in the radial inward direction towards the center of the circular curve.
The centripetal force acting on the truck is given as:
Now, the friction between the roadway and the wheels of the truck is responsible for providing the necessary centripetal force. So, frictional force is equal to the centripetal force necessary for circular motion.
Frictional force is given as:
Where, 'N' is the normal force. Since there is no vertical motion, the normal force is equal to weight of truck. So,
Therefore, frictional force,
Now, frictional force = centripetal force
Plug in the given values and solve for 'μ'. This gives,
Therefore, the coefficient of friction present between the roadway and the wheels of the truck is 0.833