Question

A naughty squirrel jumps from a tree limb onto a birdfeeder. The tree limb is 4.5 m above the ground and the top of the birdfeeder is 1.5 m above the ground. If the squirrel jumps horizontally with a velocity of 2.5 m/s then how far away in the horizontal direction can the bird feeder be for the squirrel to just make it onto the top of the feeder.

Answer 1

Answer:

Distance of 1.956 m

Explanation:

Consider the vertical plane

$S=ut+\frac{1}{2} at^2$  

where u=o, S=4.5-15=3 m

$3=0\times t+\frac{1}{2} 9.8 t^2\\t=\sqrt{0.612} \\t=0.782 s$

now consider horizontal plane

u=2.5 m/s, a=0

$S=2.5\times 0.782+0\\S=1.956 m$