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mafiozo [28]
3 years ago
8

What is transmutation?

Chemistry
2 answers:
olga nikolaevna [1]3 years ago
8 0

Answer:

the conversion of one element into another

Explanation:

edge

Tanzania [10]3 years ago
4 0

Answer:

D. the conversion of one element into another

Explanation:

Transmutation is the action of changing or the state of being changed into another form. Therefore, D is the correct answer choice.

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The day to day condition of atmosphere is known as
vovikov84 [41]

Answer:

d) atmosphere pressure

5 0
3 years ago
Read 2 more answers
Automotive air bags inflate when sodium azide, NaN3, decomposes explosively to its constituent elements. How many moles of nitro
attashe74 [19]

Answer:

2.29 g of N2

Explanation:

We have to start with the <u>chemical reaction</u>:

NaN_3~->~Na~+~N_2

The next step is to <u>balance the reaction</u>:

2NaN_3~->~2Na~+~3N_2

We can continue with the <u>mol calculation</u> using the molar mass of

NaN_3 (65 g/mol), so:

3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3

Now, with the<u> molar ratio</u> between NaN_3  and N_2  we can <u>calculate the moles</u> of N_2  (2:3), so:

0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2

With the molar mass of N_2 we can <u>calculate the grams</u>:

0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2

I hope it helps!

5 0
3 years ago
60 POINTS! PLEASE ANSWER!
Mumz [18]
I would have helped but I didn’t understand it sorry that I didn’t answer :(
6 0
3 years ago
At STP (101.3 kPa, 0 °C), what volume would 2.00 moles of oxygen gas occupy? The gas constant is 8.31
lakkis [162]

Answer:

44.8 L

Explanation:

Ideal Gas Equation -

i.e.,

PV = nRT

where,

P = pressure

V = volume

n = moles

R = universal gas constant

T = temperature

Using the information given in the question, Volume of the gas can be calculated -

P = 101.3 kPa

V = ?

n = 2.00 moles

R = 8.31

T = 0 degree C = 273.15 K

Using the above data, and putting the data in the respective formula -

PV = nRT

101.3 kPa * V = 2.00 moles * 8.31 * 273.15 K

V = 44.8 L

Hence, the volume of the given gas = 44.8 L

4 0
3 years ago
What term is used for the chemical composition of a compound​
postnew [5]

Relative molecular mass or RMM is the answer.

4 0
3 years ago
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