Answer:
In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.
Explanation:
consider marking me brainlist :)
Explanation:
colligative properties are properties that depend on the concentration of molecules or ions of the solute, but not on the identity of the solute. Colligative properties include lowering of vapour pressure, boiling point elevation, depression of the freezing point, and osmotic pressure
Answer:
Option A: 1*10^-5 M HCl has a pH of 5
Explanation:
a) 1.0 * 10^‒5 M HCl
HCl = a strong acid
pH of HCl = -log[H+]
ph of a 10^‒5 M HCl = -log(10^-5) = 5
(b) 1.0 * 10^5 M NaOH
pOH = -log(10^-5) = 5
pH = 14 -5 = 9
(c) A solution containing approximately equal concentrations of hypochlorous acid (HOCl, Ka = 2.9 * 10^‒8) and the dissolved salt of its conjugate base sodium hypochlorite (NaOCl).
pH = pKa + log[NaOCl/HOCl]
Since [NaOCl]/ [HOCl]= 1
pH = pKa +log(1)
pH = pKa
pH = -log(2.9 * 10^-8)
pH = 7.54
(d) A solution containing approximately equal concentrations of potassium hydrogen phthalate (C8H5KO4, Ka = 3.91 * 10^–6) and the dissolved salt of its conjugate base potassium phthalate.
pH = pKa +log[potassium phthalate/C8H5KO4)
Since [potassium phthalate]/[C8H5KO4] = 1
pH = pKa
pH = -log(3.91*10^-6)
pH = 5.41
e) A solution containing approximately equal concentrations of ammonia (Kb = 1.8 * 10^‒5) and the dissolved salt of its conjugate acid ammonium chloride.
pOH = pKb +log[NH4Cl]/[NH3]
Since [NH4Cl]/[NH3] = 1
pOH = pKb
pOH = 4.74
pH = 14-4.74 = 9.26
Some meringues are different and don't require the same ingredients just follow the recipe as said!!! Good luck
Answer: The stoichiometric coefficient for oxygen is .
Explanation:
A number present on the front of an atom, ion or molecule in a chemical reaction equation is called a stoichiometric coefficient.
For example,
Here, the stoichiometric coefficient for is 1, for is 1 and for is .
Thus, we can conclude that the stoichiometric coefficient for oxygen is .