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3 years ago

If you averaged 400 miles per day,about how many days would a trip of 1990 miles take

Mathematics

2 answers:

mezya [45]3 years ago

6 0

Answer:

At least 5 days

Step-by-step explanation:

400 miles per day / 1990 miles trip would take?

Cross multiplying gives;

$\frac{1990}{400}$ = 4.975 days

Rounding off the answer to nearest day gives 5 days.

worty [1.4K]3 years ago

3 0

Answer:

It would take 5 days

Step-by-step explanation:

1990/400 is 4.975 round that it is 5 so 5 days

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How do i do 3 part a ?

WINSTONCH [101]

In general the binomial expansion is

$(a+b)^n = {n \choose 0} a^0 b^n + {n \choose 1} a^1 b^{n-1} + {n \choose 2} a^2 b^{n-2} + ... + {n \choose n} a^n b^0$

So in our case, because we want ascending powers of x we'll write,

$(-3x + 1)^{11} = {11 \choose 0} (-3x)^0 1^{11} + {11 \choose 1} (-3x)^{1} 1^{10} + {11 \choose 2} (-3x)^{2} 1^9 + {11 \choose 3 } (-3x)^3 1^8 + ...$

We need to calculate the binomial coefficients:

${11 \choose 0} = 1$

${11 \choose 1} = 11$

${11 \choose 2} = \dfrac{11 \times 10}{2} = 55$

${11 \choose 3} = \dfrac{11 \times 10 \times 9}{3 \times 2} = 165$

$(-3x+1)^{11} = 1 (-3x)^0 1^{11} + 11(-3x)^{1} 1^{10} + 55 (-3x)^2 1^{9} + 165 (-3x)^3 1^8 + ...$

$(1-3x)^{11} = 1 -33 x + 495 3x^2 - 4455 x^3+ ...$

6 0

3 years ago

Gerald’s bucket lost a total of 8/5 in. of water when the hot summer sun came out. He estimated that he lost 2/15 in. an hour. H

Dahasolnce [82]

Answer:

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Step-by-step explanation:

The total amount of water lost from Gerald’s bucket is inch

The amount of water he estimated to be lost in a single hour is inch

Dividing the total water lost by water lost per hour, we can get the the total number of hours it took to lose the water.

Therefore, it took 12 hours to lose the water.

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2 years ago

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Answer:

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Step-by-step explanation:

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Katarina [22]

Answer:

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Step-by-step explanation:

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Read 2 more answers