Rotting food
hope this helps
Car B and E are speeding up, while car C is slowing down.
<h3>
What is Velocity ?</h3>
Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference.
Step-by-step explanation :
Acceleration (a) is the rate of change of velocity with time.
It is calculated by dividing the change in velocity (Δv) with the time taken for the change to occur.
In this question , the time is 10 sec in all cases.
We can divide the velocity in km/h by 3.6 to convert to m/s
In Car A
Δv = 8.33-8.33 = 0m/s
t = 10s
a = 0 m/s² ⇒car is moving with same speed and in the same direction
Car B
Δv = 5.55-0 = 5.55
t = 10
a = 5.55 / 10 = 0.555 m/s² ⇒car is speeding up
Car C
Δv = 0 - 8.33 = -8.33 m/s
t = 10
a = - 8.33/10 = -0.833 m/s² ⇒car is slowing down
Car D
Δv = 0-0 = 0
t = 10s
a = 0/10 = 0 m/s² ⇒car is at rest
Car E
Δv = 8.33 - 5.55 = 2.78
t = 10
a = 2.78/10 = 0.278 m/s²⇒car is speeding up
Learn More about acceleration here ;
brainly.com/question/13154163
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Answer:
The correct answer is A. 270L
Explanation:
We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T. The conditions STP are 1 atm of pressure and 273K of temperature.
We convert the unit of pressure in mmHg into atm:
760mmHg----1 atm
450mmHg---x= (450mmHgx 1 atm)/760mmHg=0,59atm
P1xV1/T1= P2xV2/T2
V2=((P1xV1/T1)xT2)/P2
V2=((0,59atmx500L/300K)x273K)/1 atm=<em>269,407 L</em>
Answer:
Explanation:
Area of a circular hubcap is 615 square inches
Area of a circular shaped object is given by :
r is radius of hubcap.
If the radius of the hubcap were quadrupled, it means r' = 4r. New area will become:
A' is new area
New area of the hubcap is 9840 square inches.
Answer:
chemical change is a where a variation occurs when several reactants are combined or mixed together.
physical change is a process whereby you gain or lose energy as you cool or heat it.
Explanation: