When a capacitor has a potential difference between the plates it is said to be Constant.
Both plates have different charge which signifies that one has higher potential than the other.
Therefore, when we join them in parallel, charge will flow from higher to lower. and it continued to flow until equilibrium (the entire process took only a few seconds), indicating that the potential remains constant.
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From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of fluorine = 18.99 grams
molecular mass of chlorine = 35.5 grams
Therefore:
one mole of CF2Cl2 = 12 + 2(18.99) + 2(35.5) = 120.98 grams
Therefore, we can use cross multiplication to find the number of moles in 79.34 grams as follows:
mass = (79.34 x 1) / 120.98 = 0.6558 moles
Now, one mole contains 6.022 x 10^23 molecules, therefore:
number of molecules in 0.65548 moles = 0.6558 x 6.022 x 10^23
= 3.949 x 10^23 molecules
Answer:
See the answer and explanation below , please.
Explanation:
A conjugate base is defined as that formed after an acid donates its proton.
For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:
a) HF + H20 --> F- + H30+
b) H20+ H20 --> OH- + H30+
C)H2PO3- + H20--> HPO3 2- + H30+
d) HSO4- + H20 --> SO4 2- + H30+
E) HCL02 + H20 --> CLO02 - + H30+
<h3>
Answer:</h3>
3.03 × 10²⁵ formula units KCl
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Unit 0</u>
- Reading a Periodic Table
- Writing Compounds
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
50.3 mol KCl (Potassium chloride)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
<u />
= 3.02907 × 10²⁵ formula units KCl
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
3.02907 × 10²⁵ formula units KCl ≈ 3.03 × 10²⁵ formula units KCl
