Answer:
Diagram Z
Explanation:
A cell placed into a hypotonic solution will swell and expand until it eventually burst through a process known as cytolysis.
Answer:
208.7°C was the initial temperature of the limestone.
Explanation:
Heat lost by limestone will be equal to heat gained by the water
![-Q_1=Q_2](https://tex.z-dn.net/?f=-Q_1%3DQ_2)
Mass of limestone = ![m_1=62.6 g](https://tex.z-dn.net/?f=m_1%3D62.6%20g)
Specific heat capacity of limestone = ![c_1=0.921 J/g^oC](https://tex.z-dn.net/?f=c_1%3D0.921%20J%2Fg%5EoC%20)
Initial temperature of the limestone = ![T_1=?](https://tex.z-dn.net/?f=T_1%3D%3F)
Final temperature =
=T = 51.9°C
![Q_1=m_1c_1\times (T-T_1)](https://tex.z-dn.net/?f=Q_1%3Dm_1c_1%5Ctimes%20%28T-T_1%29)
Mass of water= ![m_2=75.0 g](https://tex.z-dn.net/?f=m_2%3D75.0%20g)
Specific heat capacity of water= ![c_2=4.186 J/g^oC](https://tex.z-dn.net/?f=c_2%3D4.186%20J%2Fg%5EoC%20)
Initial temperature of the water = ![T_3=23.1^oC](https://tex.z-dn.net/?f=T_3%3D23.1%5EoC)
Final temperature of water =
=T = 51.9°C
![Q_2=m_2c_2\times (T-T_3)](https://tex.z-dn.net/?f=Q_2%3Dm_2c_2%5Ctimes%20%28T-T_3%29)
![-Q_1=Q_2](https://tex.z-dn.net/?f=-Q_1%3DQ_2)
![-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)](https://tex.z-dn.net/?f=-%28m_1c_1%5Ctimes%20%28T-T_1%29%29%3Dm_2c_2%5Ctimes%20%28T-T_3%29)
On substituting all values:
![-(62.6 g\times 0.921 J/g^oC\times (51.9^oC-T_1))=75.0 g\times 4.186 J/g^oC\times (51.9^oC-23.1^oC)](https://tex.z-dn.net/?f=-%2862.6%20g%5Ctimes%200.921%20J%2Fg%5EoC%5Ctimes%20%2851.9%5EoC-T_1%29%29%3D75.0%20g%5Ctimes%204.186%20J%2Fg%5EoC%5Ctimes%20%2851.9%5EoC-23.1%5EoC%29)
![T_1=208.7^oC](https://tex.z-dn.net/?f=T_1%3D208.7%5EoC)
208.7°C was the initial temperature of the limestone.
We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
V₁T₂ = V₂T₁
Substituting the known values,
(0.456 L)(65 + 273.15) = (3.4 L)(T₁)
T₁ = 45.33 K
Answer:
It's a soft metal, reactive and with a low melting point, with a relative density of 0,97 at 20ºC (68ºF)