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3 years ago

6th grade science help me please ((:

Chemistry

1 answer:

aev [14]3 years ago

5 0

Answer:

Condensation forms tiny water droplets.

Explanation:

It cools the temperature and the air become less denser.

hope it helps!

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Consider the equilibrium

vladimir1956 [14]

Answer:

$Kp^{1000K}=0.141\\Kp^{298.15K}=2.01x10^{-18}$

$\Delta _rG=1.01x10^5J/mol$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$C_2H_6(g)\rightleftharpoons H_2(g)+C_2H_4(g)$

Thus, Kp for this reaction is computed based on the given molar fractions and the total pressure at equilibrium, as shown below:

$p_{C_2H_6}^{EQ}=2bar*0.592=1.184bar\\p_{C_2H_4}^{EQ}=2bar*0.204=0.408bar\\p_{H_2}^{EQ}=2bar*0.204=0.408bar$

$Kp=\frac{p_{C_2H_4}^{EQ}p_{H_2}^{EQ}}{p_{C_2H_6}^{EQ}}=\frac{(0.408)(0.408)}{1.184}=0.141$

Now, by using the Van't Hoff equation one computes the equilibrium constant at 298.15K assuming the enthalpy of reaction remains constant:

$Ln(Kp^{298.15K})=Ln(Kp^{1000K})-\frac{\Delta _rH}{R}*(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=Ln(0.141)-\frac{137000J/mol}{8.314J/mol*K} *(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=-40.749\\\\Kp^{298.15K}=exp(-40.749)=2.01x10^{-18}$

Finally, the Gibbs free energy for the reaction at 298.15K is:

$\Delta _rG=-RTln(Kp^{298.15K})=8.314J/mol*K*298.15K*ln(2.01x10^{-18})\\\Delta _rG=1.01x10^5J/mol$

Best regards.

3 0

4 years ago

Which of the following is a physical change?

yan [13]

Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.

6 0

3 years ago

A balloon inflated with three breaths of air has a volume of 1.7 L. At the same temperature and pressure, what is the volume of

Karolina [17]

Ans: The final volume of the balloon is 4.5 L

Given:

Volume of balloon inflated with 3 breaths = 1.7 L

To determine:

Volume of balloon after a total of 3+5 = 8 breaths

Explanation:

Volume of the balloon per breath = 1.7 L * 1 breath/3 breaths = 0.567 L

Final volume of balloon after 8 breaths = 0.567 L * 8 breath/1 breath

= 4.536 L

7 0

3 years ago

After an experiment is complete and has been published, what process makes sure the results are reliable?

slavikrds [6]

Answer:

B. Peer review

Explanation:

Peer review ensures that the results of an experimental procedures are consistent are reliable and they meet their objective statement.

When peers which are professionals in a field of study subjects the results from an experiment into a test, they can give their own verdict as to wether such findings are consistent and reliable with the problem in view.

7 0

3 years ago

How many moles of butane (C4H10) must be burned in an excess of O2 to produce

Sedbober [7]

Answer: 6,25 moles

Explanation: mark amount of butane x.

From equation you can calculate x in a following way:

2/x = 8/25. 8x = 50. And x = 6,25

4 0

3 years ago