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skelet666 [1.2K]
3 years ago
9

办理教留服学位学历认证Q/微29304199美国堪萨斯KU毕业证文凭学位证书offer操办堪萨斯留信认证成绩单

Chemistry
1 answer:
astra-53 [7]3 years ago
8 0

办理教留服学位学历认证Q/微29304199美国堪萨斯KU毕业证文凭学位证书offer操办堪萨斯留信认证成绩单 what欧式

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A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°c. what is the magnitude of k at 75.0°c if ea =
IgorC [24]
According to this formula:
K= A*(e^(-Ea/RT) when we have K =1.35X10^2 & T= 25+273= 298K &R=0.0821
Ea= 85.6 KJ/mol So by subsitution we can get A:
1.35x10^2 = A*(e^(-85.6/0.0821*298))
1.35x10^2 = A * 0.03
A= 4333
by substitution with the new value of T(75+273) = 348K & A to get the new K
∴K= 4333*(e^(-85.6/0.0821*348)
  = 2.16 x10^2
8 0
2 years ago
All elements are pure substances.<br><br> True<br><br> False
oee [108]
It can be a compound or a single element. An element is a pure substance that cannot be separated into simpler substances by chemical or physical means. There are about 117 elements, but carbon, hydrogen, nitrogen and oxygen are only a few that make up the largest portion of Earth.
hopefully that helps
5 0
3 years ago
Saltpeter is a compound made of potassium (k), nitrogen (n), and oxygen (o). every 100.00 g of saltpeter contains 38.67 g potass
xeze [42]
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
                          = 100 - (38.67 + 13.86)
                          = 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams

Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
5 0
2 years ago
Read 2 more answers
Suppose we have a compound that is 4.330 % Li, 22.10 % Cl, 39.89 % O, and 33.69 % H2O. What is the compounds formula?
amid [387]

The  formula   of compound is   LiClO4.3H2O


      <em><u>calculation</u></em>

  • <em><u>  </u></em>find the mole  of  each element

        that is  moles for Li,Cl,O and that of H2O

  • moles = % composition/ molar mass

       For Li = 4.330/ 6.94 g/mol=  0.624 moles

             Cl=22.10/35.5=0.623  moles

           39.89/16 g/mol =2.493  moles

           H20=  33.69/18 g/mol=  1.872  moles

  • find  the mole ratio  by  dividing each moles by smallest number of mole ( 0.624 moles)

        that  is  for  Li= 0.624/0.623=  1

                             Cl= 0.623/0.623=1

                             O = 2.493/0.623 =4

                          H2O= 1.872/0.623=3

<h3>Therefore the formula=LiClO4.3H2O</h3><h3 />
8 0
3 years ago
a solution is prepared by dissolving 55g of CaCl2 into 300g of water. if the Kf of water is -1.86 c/m, shat is the freezing poin
Zepler [3.9K]

Answer:

Relation between , molality and temperature is as follows.

                T =

It is also known as depression between freezing point where, i is the Van't Hoff factor.

Let us assume that there is 100% dissociation. Hence, the value of i for these given species will be as follows.

         i for  = 3

          i for glucose = 1

          i for NaCl = 2

Depression in freezing point will have a negative sign. Therefore, d

depression in freezing point for the given species is as follows.

       

                 =

       

                  =

     

                   =

Therefore, we can conclude that given species are arranged according to their freezing point depression with the least depression first as follows.

                    Glucose < NaCl <

Explanation:

3 0
3 years ago
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