Answer: F<em>or the volume of gas changes from 5L to 3L, what will be the new pressure? What law did you use and why</em>
<em>For example, if you want to calculate the volume of 40 moles of a gas under a pressure of 1013 hPa and at a temperature of 250 K, the result will be equal to: V = nRT/p = 40 * 8.3144598 * 250 / 101300 = 0.82 m³</em>
Explanation:
Brainerlist
Answer:
What best describes the concept of weight is the force on an object due to its mass and gravity.
Explanation:
Weight is the force with which gravity pulls a body or object towards the earth. It is a physical unit that involves both the force of gravity and the mass that an object has.
In general, the terms mass and weight are different, being the mass a characteristic of the body -without influence of other factors- and the weight is the force with which the gravity pushes the mass of that same body.
Regarding the other options:
- <em>The amount of space an object takes up
, corresponds to the volume of a body.</em>
- <em>The amount of matter in an object
, corresponds to the mass.</em>
- <em>The force on an object due to its speed and location, is related to the movement of a body.</em>
Answer:
option C is correct (250 g)
Explanation:
Given data:
Half life of carbon-14 = 5700 years
Total amount of sample = 1000 g
Sample left after 11,400 years = ?
Solution:
First of all we will calculate the number of half lives passes during 11,400 years.
Number of half lives = time elapsed/ half life
Number of half lives = 11,400 years/5700 years
Number of half lives = 2
Now we will calculate the amount left.
At time zero = 1000 g
At first half life = 1000 g/2 = 500 g
At second half life = 500 g/2 = 250 g
Thus, option C is correct.
2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O
<em>Step 1</em>. Write the <em>condensed structural formula</em> for 2,3-dimethylbutane.
(CH_3)_2CHCH(CH_3)_2
<em>Step 2</em>. Write the <em>molecular formula</em>.
C_6H_14
<em>Step 3</em>. Write the <em>unbalanced chemical equation</em>.
C_6H_14 + O_2 → CO_2 + H_2O
<em>Step 4</em>. Pick the <em>most complicated-looking formula</em> (C_6H_14) and balance its atoms (C and H).
<em>1</em>C_6H_14 + O_2 → <em>6</em>CO_2 + <em>7</em>H_2O
<em>Step 5</em>. Balance the <em>remaining atoms</em> (O).
1C_6H_14 + (<em>19/2</em>)O_2 → 6CO_2 + 7H_2O
Oops! <em>Fractional coefficients</em>!
<em>Step 6</em>. <em>Multiply all coefficients by a number</em> (2) to give integer coeficients..
2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O
