Answer:
Speed of the wreckage = 49.29 km/hr
Explanation:
This question is solved simply by using the conservation of momentum law.
The momentum of the three moving bodies are calculated below:
Momentum of Car 1 : 1100 * 55 = 60500 kg.km/hr
Momentum of Truck : 480 * 37 = 17760 kg.km/hr
Momentum of Car 2 : 1300 * 49 = 63700 kg.km/hr
Total mass of all three vehicles: 1100 + 480 + 1300 = 2880 kg
The final momentum equals the initial momentum if it is conserved. Thus we have the following equation:
Final Momentum = Initial Momentum
Final Velocity * Total mass = Momentum of all three vehicles combined
Final Velocity * 2880 = 60500 + 17760 + 63700
Final Velocity = 49.29 km/hr
Answer:
- 0.25m/s²
Explanation:
Given parameters:
Initial velocity = 40m/s
Final velocity = 30m/s
Time taken = 40s
Unknown:
Acceleration of the car = ?
Solution:
Acceleration is the rate of change of velocity with time.
So;
Acceleration = 
Acceleration = 
= - 0.25m/s²
This implies that the car will decelerate at a rate of 0.25m/s²
When the car speeds up, slows down, or goes around a curve,
passengers need a force applied to them to make them do the
same thing, otherwise they won't keep up with the car.
The force on the passenger is applied by means of friction between
the upholstery and the seat of his pants, and also by the seat-back
or his seat-belt.
Is there a multiple choice?
