A ferris wheel with radius r rotates freely about its central

An AP Physics student is attempting an FRQ problem. They arrive at the following expression for the total distance an object has

zysi [14]

The student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).

<h3>Total distance traveled by an object</h3>

The total distance traveled by an object projected upward is calculated from third equation of motion a shown below.

<h3>Equation for the motion of the object</h3>

v² = u² - 2gh

where;

v is final velocity
u is initial velocity
g is acceleration due to gravity

at maximum height, the final velocity is zero, v = 0

0 = u² - 2gh

2gh = u²

h = u²/2g

The equation for the total distance an object has traveled during upward projection is "h = u²/2g".

<h3>Dimension of the student's answer;</h3>

d = (2vh)/g = (m/s x m) / (m/s²) = (m²/s) / (m/s²) = m.s

Thus, the student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).

Learn more about distance here: brainly.com/question/2854969

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7 0

2 years ago

An Object is located 16 cm in front of a converging lens with focal length 12 cm. To the right of the converging lens, separated

ExtremeBDS [4]

Answer:

image is located at 22.5cm to the left of diverging lens.

Explanation:

In this question we have given,

object distance from converging lens,u=-16cm

focal length of converging lens, $f_{c}=12cm$

focal length of diverging lens, $f_{d}=-10cm$

distance between converging and diverging lens=20cm

we have to find location of final image,v=?

Here we will first find the location of image formed by converging lens

we know that u, v and $f_{c}$ are related by following formula

$\frac{1}{f_{c}} =\frac{1}{v}- \frac{1}{u}$ .............(1)

put values of $f_{c}$ and u in equation (1)

we got,

$\frac{1}{12} =\frac{1}{v}- \frac{1}{-16}$

$\frac{1}{12}-\frac{1}{16} =\frac{1}{v}$

$\frac{16-12}{16\times 12} =\frac{1}{v}$

or

$v=\frac{16\times 12}{16-12}\\ v=48cm$

The image is located 48 cm to the right of the converging lens. This image is real and inverted.

This image will object for the diverging lens which is now located (48-20=18) cm at the right hand side of diverging lens

it means,

u=18cm

we know that u, v and $f_{d}$ are related by following formula

$\frac{1}{f_{d}} =\frac{1}{v}- \frac{1}{u}$ .............(2)

put values of $f_{d}$ and u in equation (2)

$\frac{1}{-10} =\frac{1}{v}- \frac{1}{18}$

$\frac{1}{-10}+\frac{1}{18} =\frac{1}{v}$

$\frac{-18+10}{10\times 18} =\frac{1}{v}$

or

$v=\frac{10\times 18}{10-18}\\ v=-22.5cm$

It means image is located at 22.5cm to the left of diverging lens.

7 0

3 years ago

Answer the assignment questions using the World Geology map in this lesson and/or the earth's lithospheric plates map in the ass

Advocard [28]

3 I think sorry if wrong

3 0

3 years ago

Complete the sentences below correctly. Stunt Car A and Stunt Car B are identical cars with the same mass of 48.9 kg. They are b

ivann1987 [24]

Answer:

Stunt Car A experiences a large force over a short period of time. Stunt Car B experiences a small force over a long period of time. Because of the force experienced by Stunt Car A, it will sustain more damage than Stunt Car B.

Explanation:

Both cars have the same mass and velocity, therefore they have the same momentum. During the collision, the total momentum of the car A and brick wall is conserved as well as the total momentum of the car B and the pile of leaves.

However, if we are to investigate the damage on each car, we should look at the cars not the whole system. So, the momentum difference between the cars gives us the impulse that the car felt.

$\vec{J} = \Delta \vec{P}\\\vec{F}\Delta t = \vec{P}_2 - \vec{P}_1$