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bazaltina [42]
3 years ago
9

Unpolarized light with an intensity of (25.0 A) units is passed through two successive polarizing filters, the first with its po

larization axis aligned with the vertical and the second with its polarization axis rotated (55.0 B) from the vertical. Find the intensity of the light after passing through the two polarizing filters.
Physics
1 answer:
N76 [4]3 years ago
6 0

Answer:

The intensity of the light after passing through the two polarizing filters is 4.00 units

Explanation:

Io = 25 + A

= 25 + 9

= 34

Intensity of light through first polarizer,

I1 = Io/2

= 34/2

= 17 units

angle between axis of frist and second polarizers, theta = 55 + 6

= 61 degrees

Intensity of light passing through second polarizer,

I2 = I1*cos^2(theta)

= 17*cos^2(61)

= 4.00 units

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The tidal lung volume of human breathing, representing the amount of air inhaled and exhaled in a normal breath, is 500 cm3. (As
Darina [25.2K]

Answer:

Explanation:

Temperature of air = 18°C = 273 + 18 = 291 K .

volume = 500 cc = 0 .5 litre .

pressure = one atmosphere ( atm) .

From gas equation , we can calculate this volume at NTP  as follows.

volume = .5 x ( 273 / 291  ) litre

= 0.469 litre .

In any gas at NTP , 22.4 litre contains 6.02 x 10²³ molecules

.469 litre will contain  6.02 x 10²³ x .469 / 22.4 molecules

= 126 x 10²⁰ molecules .

b )

one mole = 6.02 x 10²³ molecules

6.02 x 10²³ molecules  has weight of 28.96 grams

126 x 10²⁰ molecules has weight of 28.96 x 126 x 10²⁰ / 6.02 x 10²³ grams

= .606 gram .

c )

volume of all the air in the atmosphere = volume of sphere

=  4 / 3 x π  x R³

= ( 4 / 3) x 3.14 x (999.5 x 10³ )³ m³

= 4.18 x 10¹⁸ m³

density of air = 1.225 kg / m³

mass of air = 1.225 x 4.18 x 10¹⁸ kg

= 5.12 x 10¹⁸ kg

d )

volume of air inhaled by 7 billion people

= . 5 x 7 x 10⁹ litre

= 3.5 x 10⁶ m³ .

Total volume of air in atmosphere = 4.18 x 10¹⁸ m³

required percentage

= 3.5 x 10⁶ x 100 /  4.18 x 10¹⁸

= .8373 x 10⁻¹⁰ % .

6 0
3 years ago
Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiem
statuscvo [17]

Answer:

t = 0.33h = 1200s

x = 18.33 km

Explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

x=x_o+v_1t    (1)

xo = 10 km

v1 = 55km/h

car 2:

x'=v_2t    (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}

t=\frac{10km}{85km/h-55km/h}=0.33h*\frac{3600s}{1h}=1200s

The position in which both cars coincides is:

x=(55km/h)(0.33h)=18.33km

6 0
3 years ago
Tides are caused by the force of gravity from the sun and moon acting on Earth.
vfiekz [6]
Yes that answer is correct because sometimes tides cause waves to happen
4 0
3 years ago
Read 2 more answers
Despite the gases, dust, and stars that compose the universe, it is still mostly made up of ____________________.
ivann1987 [24]

Answer:

space

Explanation:

5 0
3 years ago
A street light is on top of a 8 foot pole. Joe,
zubka84 [21]
8/4 = y/y-x

8y - 8x  = 4y

y = 2x

y = 2 x 4

y = 8

Hope this helps
5 0
3 years ago
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