All categories

3 years ago

What is the correct order of operations for simplifying the expression 2 – 3x + 5+7(y – 5x)2 + 0.

Mathematics

2 answers:

Mazyrski [523]3 years ago

5 0

Answer:

D. square the binomial, distribute 7 inside the parentheses, and then combine like terms

Step-by-step explanation:

edge 2021

Liono4ka [1.6K]3 years ago

4 0

Answer:

The given expression is ,2 - 3 x + 5 + 7(y - 5 x)^{2} + x2−3x+5+7(y−5x)

1 . First we will write the term having highest degree and then move to lowest degree,

→ 7 (y -5 x)² + x -3 x+2+5

2. Adding and subtracting like terms

→7 (y -5 x)² - 2 x+7

Expanding the term in brackets

→ 7(y² + 25 x² -10 x y) - 2 x + 7

Use distributive property

→ 7 y² + 175 x² -70 x y -2 x +7→[Wrote the terms from highest degree to lowest degree]

You might be interested in

A shirt regularly priced at $36.00 was on sale for 25% off.

luda_lava [24]

36 x 25%
36 x .25
36 x .25 = 9.00
36 - 9.00
36 - 9.00 = $27
C. $27.00

3 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

*****urgent help ****Write 2447457.627 in standard form to a appropriate degree of accuracy pls i need help

erica [24]

Answer:

2.447457627 x 10^6

Step-by-step explanation:

If this helped can i have Brainliest

5 0

3 years ago

The answer is 915 / 7

Naily [24]

Answer:

If you want 915/7 simplified, it is 130.714285714.

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

8+345737377948585848484

iris [78.8K]

Answer:

3.4573738e+20

Step-by-step explanation:

6 0

3 years ago