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Damm [24]
3 years ago
6

3. When 10.0 g of a pure compound was analyzed, it was found to contain 3.65 g of K, 3.33 g of CI,

Chemistry
1 answer:
vampirchik [111]3 years ago
5 0
Convert all the grams to moles first.

K - 3.65 g / 39.1 g/mol = 0.0934 mol
Cl - 3.33 g / 35.45 g/mol = 0.0939 mol
O - 3.02 g / 16 g/mol = 0.189 mol

Divide them all by the smallest number of moles (0.0934 moles of K) to get whole numbers.

K - 0.0934/0.0934 = 1
Cl - 0.0939/0.0934 ≈ 1
O - 0.189/0.0934 ≈ 2

KClO2
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<h3>Explanation</h3>

Relative strength of intermolecular forces in small molecules:

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It takes two conditions for molecules in a substance to form <em>hydrogen bonds</em>.

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HCl molecules are polar. The H-Cl bond is fairly polar. The HCl molecule is asymmetric, such that the dipole won't cancel out. The molecule is overall polar. Both dipole-dipole interactions and London Dispersion Force are possible between HCl molecules. However, dipole-dipole interactions are most predominant among the two.

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Answer/Explanation:

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E Notation: 3.45e5

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</span>In chemistry, sigma bonds (σ bonds) are the strongest type of covalent chemical bond. They are formed by head-on overlapping between atomic orbitals. Sigma<span> bonding is most simply defined for diatomic molecules using the language and tools of symmetry groups.
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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