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3 years ago

Is the mass of an object measured with scale, yes or no

Physics

1 answer:

mamaluj [8]3 years ago

7 0

Answer:

No.

Explanation:

The scale actually measures the force that the object does against it, and that force is called the weight.

Such that if we have an object with mass M and we are on Earth, where the gravitational acceleration is g, the weight is:

W = M*g

Now, there is a unit called "kilogram-force"

Such that on Earth, an object that has a mass of 10 kilograms, weighs 10 kilograms-force.

Then from the weight measure, we can instantly know the mass of the object, but the thing that is being measured is the weight, not the mass.

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Draw Graph for the derivation of three equations of Motion

Over [174]

Answer:

Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say

Explanation:

Derive v = u + at by Graphical Method. Consider the velocity – time graph of a body shown in the below Figure

Derive s = ut + (1/2) at2 by Graphical Method. Velocity so time graph to derive the equations of motion.

Derive v2 = u2 + 2as by Graphical Method. Velocity–Time graph to derive the equations of motion.

I hope you understand now

enjoy your day

#Captainpower :)❤❤

5 0

2 years ago

An object is moving with a constant velocity of 278 m/s. How long will it take it to travel 7500 m, using the formula Delta X=Vt

rusak2 [61]

If the velocity is constant then the acceleration of the object is zero.
$a=0 (m/s^2)$
Thus when we apply the equation
$\Delta X=vt+(at^2/2)$
It remains
$\Delta X =vt$
or equivalent
$t=(\Delta X/v) =7500/278 =26.98 (seconds)$

7 0

3 years ago

3. What is the gravitational force between a 70 kg physics student and her 1 kg textbook, at a distance of 1 meter? (This number

Rina8888 [55]

ANSWER

$\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}$

EXPLANATION

Parameters given:

Mass of the student, M = 70 kg

Mass of the textbook, m = 1 kg

Distance, r = 1 m

To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:

$F=\frac{GMm}{r^2}$

where G = gravitational constant

Therefore, the gravitational force acting between the student and the textbook is:

$\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\ \\ F=4.67*10^{-9}\text{ }N \end{gathered}$

That is the answer.

6 0

1 year ago

A marble is dropped from rest and falls for 2.3 seconds. Find its final velocity.

juin [17]

Answer:

23 m/s downward

__________________________________________________________

Taking the downward direction as positive

We are given:

Initial velocity of the marble (u) = 0 m/s

Time interval (t) = 2.3 seconds

Final velocity (v) = x m/s

Solving for the Final velocity:

Acceleration of the Marble:

We know that gravity will make the marble accelerate at a constant acceleration of 10 m/s

Final velocity:

v = u + at [First equation of motion]

x = 0 + (10)(2.3) [replacing the given values]

x = 23 m/s

Hence, after 2.3 seconds, the marble will move at a velocity of 23 m/s in the downward direction

4 0

2 years ago

If an egg person starts from rest then falls directly downward and hits the ground with a velocity of 12 m/s but

Anni [7]

Answer:

Explanation: Determine the gravitational acceleration. ...

Decide whether the object has an initial velocity. ...

Choose how long the object is falling. ...

Calculate the final free fall speed (just before hitting the ground) with the formula v = v₀ + gt

6 0

2 years ago

Read 2 more answers

Is the mass of an object measured with scale, yes or no​

Is the mass of an object measured with scale, yes or no