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Ivahew [28]
3 years ago
14

An object with a mass 4.0 kg has a momentum of 64 kgm/s . How fast is the object traveling ?

Physics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

The object will travel at the speed of 16 m/s.

Explanation:

Given

  • Mass m = 4.0 kg
  • Momentum p = 64 kgm/s

To determine

How fast is the object traveling?

<u>Important Tip:</u>

The product of the mass and velocity of an object —  momentum.

Using the formula

p = mv

where

  • m = mass
  • v = velcity
  • p = momentum

Thus, in order to determine the speed of the object, all we need to do is to substitute p = 64 and m = 4 in the formula

p = mv

64\:=\:4\times v

switch the equation

\:4\times \:v\:=64

divide both sides by 4

\frac{4v}{4}=\frac{64}{4}

simplify

v=16 m/s

Therefore, the object will travel at the speed of 16 m/s.

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now using above equation

93.8^2 = 62.1^2 + b^2 - 2*62.1*b * cos46.6

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by solving above quadratic equation we have

b = 124.9 m

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4 0
3 years ago
A spacecraft and a staellite are at diametrically opposite position in the same circular orbit of altitude 500 km above the eart
Tanya [424]

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

             b)  8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = \frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }  --  ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft  

<u>a) determine the increase in speed </u>

V = v - \sqrt{\frac{gR^2}{R + h} }  

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = \frac{3t}{2}

 = \frac{3*5670.76}{2}  =  8506.1 secs

attached below is the remaining part of the detailed solution

5 0
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Snezhnost [94]

Answer:

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Explanation:

The current density is

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now let's analyze each case

a) R₂ has an area 2A₀ and a length L₀ that R₁

b) R₃ has an area Ao and a length 3L₀ what R₁

we can see that all the area is given in relation to the resistance R₁

 

the current density in R₁ is

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the current density in R₂

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the current density in R₃

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         j₂ < j₁ = j₃

therefore resistor R₂ has the lowest current density

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VARVARA [1.3K]
The answer is <span>C. 3000 kg.</span>
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The answer is attached.

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