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3 years ago

How does water vapor effect the way you breathe and how you can feel the climate change around you?

Chemistry

2 answers:

Anika [276]3 years ago

8 0

Fills your lungs with air that I’m not great

Burka [1]3 years ago

3 0

Answer:

Water vapour is an efficient greenhouse emission, because it will absorb radio wave radiation and radiates it back to the surface, so contributive to warming. when put next to alternative greenhouse gases, water vapour stays within the atmosphere for a way shorter amount of your time, However, When you exhale and it's cold outside, though, the vapour in your breath loses its energy quickly. instead of continued to maneuver freely, the molecules begin to pack themselves closely along. As they are doing this, they cut down and start to alter into either liquid or solid varieties of water.

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Counting Atoms in Compound 1. 4K2CO3 K=___ C=___ O=___

VARVARA [1.3K]

K= 8
C=4
O= 12

The number after the letter shows how much of that atom there is.

The 4 shows there is 4 of each after it, so 4 of the K2, C, and O3. You would want to multiply the K2, C, and O3 by 4.

8 0

4 years ago

Read 2 more answers

Why does the dilution equation, M 1 V 1 = M 2 V 2, work?

valentina_108 [34]

Answer:

d) The dilution equation works because the number of moles remains the same.

Explanation:

Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and M₁V₁ = 1 mol.

Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.

The volume has doubled, but the volume has halved, and M₂V₂ = 1 mol.

b) Wrong. The molar concentration changes on dilution.

c) Wrong. The volume changes on dilution.

a) Wrong, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula M₁V₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.

6 0

4 years ago

Read 2 more answers

Recovery standards are a necessary tool for determining exactly how much of a particular analyte you are able to extract from a

Dafna11 [192]

Answer:

2.05mg Fe/ g sample

Explanation:

In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.

In the problem you recover 3.5mg Fe / 1.0101g sample: 3.465mg Fe / g sample. As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:

3.465 / 4×100 = 86,6%

As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:

1.7mg Fe / 0.9582g sample× (100/86.6) = 2.05mg Fe / g sample

I hope it helps!

5 0

4 years ago

If you were to observe a handful of soil, what materials would you MOST LIKELY find?

hjlf

Your answer is A. Weathered rocks and decomposed organic remains.

7 0

4 years ago

Write balanced equations for each of the processes, choosing from the following substances as reactants: BaCl2 O2 H2SO4 HNO3 C2H

marishachu [46]

Answer:

BaCl₂ and H₂SO₄

Explanation:

The reaction is the precipitation of BaSO₄ from solution.

This means that our reactants must contain the Ba ion and SO₄²⁻ ion. The reactants that meet this criteria are the; BaCl₂ aand H₂SO₄

The reaction is given as;

BaCl₂ + H₂SO₄ --> BaSO₄ + 2HCl

8 0

4 years ago