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Marysya12 [62]
2 years ago
12

Fill in the blank The (blank) of a rock is a result of its mineral composition.

Chemistry
1 answer:
Lana71 [14]2 years ago
7 0
Fill in the blank
The (blank) of a rock is a result of its mineral composition.

Answer:

Color
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2 . a) b) (1) List three oxides of nitrogen ( 3ks) State Charles law (2mks) (111) A given mass of gas occupies 300cm at 900mmHg
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ask correctly so that your points cant make fun of others

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2 years ago
Hydrogen bonding is most often seen _____. see concept 2.3 (page 38) view available hint(s) hydrogen bonding is most often seen
Evgesh-ka [11]
<h3><u>Answer;</u></h3>

When hydrogen is covalently bonded to an electronegative atom

<h3><u>Explanation;</u></h3>
  • Hydrogen bonding is a special type of dipole-dipole attraction between molecules. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom.
  • Highly electronegative atoms attract shared electrons more strongly than hydrogen does, resulting in a slight positive charge on the hydrogen atom. The slightly positive hydrogen atom is then attracted to another electronegative atom, forming a hydrogen bond.

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3 years ago
An atom with six protons and eight neutrons is a(n)___
mylen [45]

Answer:

standard carbon atom

Explanation:

7 0
3 years ago
Read 2 more answers
What is the name for a compound that forms between one Nitrogen and 3 Chlorines
ivann1987 [24]

in the picture below

4 0
2 years ago
A sample of 5.30 mLmL of diethylether (C2H5OC2H5;density=0.7134g/mL)(C2H5OC2H5;density=0.7134g/mL) is introduced into a 6.50 L L
lilavasa [31]

Answer:

1.16atm

Explanation:

We are going to derive the mass of ether from density

mass=density *volume

Also moles=mass/molecular mass

molar mass C2H5OC2H5 =74.12 g/mole

the density of ether is 0.7134 g/ml

mass C2H5OC2H5 = 5.30 ml x 0.7134 g/ml = 3.78 g

moles C2H5OC2H5 =3.78 g x 1 mole/74.12 g = 0.0509 moles

PV = nRT where P=?; n=0.0509 moles; V=6.50L; R=0.0821 Latm/Kmol; T=35ºC +273 = 308K

P = nRT/V = 0.0509)(0.0821)(308)/6.50

P = 0.198 atm (to 3 significant figures (this is the partial pressure of diethyl ether).  

TOTAL PRESSURE

P1+p2+p3

= 0.198 atm + 0.750 atm + 0.207 atm =1.1550atm

1.16atm(3 significant figures)

5 0
3 years ago
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