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Anastasy [175]
3 years ago
8

A chemist prepares a solution of sodium thiosulfate by measuring out of sodium thiosulfate into a volumetric flask and filling t

he flask to the mark with water. calculate the concentration in of the chemist's sodium thiosulfate solution. round your answer to significant digits.
Chemistry
1 answer:
marshall27 [118]3 years ago
4 0

Mass of sodium thiosulfate Na_{2}S_{2}O_{3} is 110. g

Volume of the solution is 350. mL

Calculating the moles of sodium thiosulfate:

110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}} = 0.696 molNa_{2}S_{2}O_{3}

Converting the volume of solution to L:

350. mL * \frac{1 L}{1000 mL} = 0.350 L

Finding out the concentration of solution in molarity:

\frac{0.696 mol}{0.350 L} =  1.99 mol/L

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In one experiment, the reaction of 1.00 mercury and an excess of sulfur yielded 1.16g of a sulfide of mercury
Nuetrik [128]

<u>Answer and Explanation:</u>

Mercury combines with sulfur as follows -

Hg + S = HgS

Hg = 200,59

S = 32,066 Therefore 1.58 g of Hg will react with -

1.58 multiply with 32,066 divide by 200,96 of sulfur.

= 0.25211 g S

This will form 1.58 + 0.25211 g HgS  = 1.83211 g HgS

The amount of S remaining = 1.10 - 0.25211  = 0.84789 g

5 0
3 years ago
1. Newton’s second law of motion describes the relationship between force, mass, and acceleration. Write the equation.
rjkz [21]

Answer:

F=ma where F = force in N, m = mass in g and a = acceleration in m/s^{2}

7 0
3 years ago
The reaction between nitrogen and hydrogen to produce ammonia is described by the equilibrium reaction:
laiz [17]

Answer:

Explanation:

The formation of ammonia that occurred by the reaction of nitrogen and ammonia is expressed as:

3H_{2(g)} + N_{2(g)} ⇄ 2NH_{3(g)}

where;

The reactants are:

Hydrogen and nitrogen

The product is ammonia.

For the reaction, the equilibrium constant can be expressed as:

K = \dfrac{[product]}{[reactants]}

K = \dfrac{[NH_3]^2}{[N_2]^3[H_2]^3}

From the equilibrium constant conditions, the formation of ammonia and its decomposition due to its reversible reaction back to hydrogen and nitrogen are equal.  It implies that the rate of the forward reaction is also equal to that of the backward reaction.

Thus, during when equilibrium is obtained;

Hydrogen, Nitrogen, and Ammonia are present.

8 0
3 years ago
What volume (in L) of oxygen will be required to produce 77.4 L of water vapor in the reaction below?
Nostrana [21]

Answer:

For the production of 77.4 L water 90.3 L oxygen is required.

Explanation:

Given data:

Volume of oxygen required = ?

Volume of water produced = 77.4 L

Solution:

Chemical reaction equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

1 mole = 22.414 L

There are 6 moles of water = 6×22.414 = 134.5 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

Now we will compare the litters of water and oxygen:

                              H₂O           :              O₂    

                              134.5         :              156.9

                                77.4         :             156.9/134.5×77.4 =90.3 L

So for the production of 77.4 L water 90.3 L oxygen is required.

8 0
3 years ago
A sample of carbon dioxide occupies a volume of 2.50L liters at 300kPa pressure and a temperature 273K. What pressure would the
Drupady [299]

Answer:

The answer to your question is:    P2 = 846 kPa

Explanation:

Data

V1 = 2.5 l

P1 = 300 kPa

T1 = 273 °K

P2 = ?

V2 = 1 l

T2 = 308°K

Formula

             \frac{P1V1}{T1}  = \frac{P2V2}{T2}

             P2 = \frac{P1V1T2}{T1V2} \\

             P2 = \frac{(300)(2.5)(308)}{(273)(1)} \\

            P2 = \frac{231000}{273} \\

            P2 = 846 kPa

5 0
3 years ago
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