1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ne4ueva [31]
3 years ago
6

1. A student sees tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drinks. The student

squeezes the bottle.
a. The bubbles will shrink, and some may vanish.
b. The bubbles will grow, and more may appear.
c. The bubbles won't change.
2. A student has two unopened 33cL cans containing carbonated water. Can A has been stored in the garage (32°C) and can B has been stored in the fridge (8°C). The student opens one can at the time, both cans make a fizz.
a. Can A will make a louder and stronger fizz than can B.
b. Can B will make a louder and stronger fizz than can A.
c. The fizz will be the same for both cans.
d. There is not enough information to predict which can will make the louder fizz.
Chemistry
1 answer:
Lina20 [59]3 years ago
3 0

Answer:

1) The bubbles will grow, and more may appear.

2)Can A will make a louder and stronger fizz than can B.

Explanation:

When you squeeze the sides of the bottle you increase the pressure pushing on the bubble, making it compress into a smaller space. This decrease in volume causes the bubble to increase in density. When the bubble increases in density, the bubble will grow and more bubbles will appear. Therefore, Changing the pressure (by squeezing the bottle) changes the volume of the bubbles. The number of bubbles doesn't change, just their size increases.

Carbonated drinks tend to lose their fizz at higher temperatures because the loss of carbon dioxide in liquids is increased as temperature is raised. This can be explained by the fact that when carbonated liquids are exposed to high temperatures, the solubility of gases in them is decreased. Hence the solubility of CO2 gas in can A at 32°C is less than the solubility of CO2 in can B at 8°C. Thus can A will tend to make a louder fizz more than can B.

You might be interested in
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

pKa2 = -log Ka

       = -log 6.2x10-8

       = 7.21

We know Henderson-Hasselbalch equation

pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
3 years ago
How much heat (in kj) is released when 3.600 mol naoh(s) is dissolved in water? (the molar heat of solution of naoh is â445.1 kj
Fantom [35]
<span>-1602 kj

Sauce:me

Your welcome
</span>
8 0
3 years ago
Read 2 more answers
How much energy is needed to completely boil a 5.05g sample of water?
Keith_Richards [23]

Given what we know, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

<h3>Why does it take this much energy to boil the water?</h3>

We arrive at this number by taking into account the energy needed to boil 1g of water to its vaporization point. This results in the use of 2260 J of heat energy. We then take this number and multiply it by the total grams of water being heated, in this case, 5.05g, which gives us our answer of 11.4 kJ of energy required.

Therefore, we can confirm that the amount of heat energy that would be required in order to boil 5.05g of water is that of 11.4kJ of heat.

To learn more about the behavior of water visit:

brainly.com/question/1416592?referrer=searchResults

8 0
2 years ago
Boron carbonate decomposes into boron oxide and carbon dioxide. How many moles of CO2
Paul [167]
<h3>Answer:</h3>

15 moles

<h3>Explanation:</h3>

The decomposition of boron carbonate is given by the equation;

B₂(CO₃)₃(s) → B₂O₃(s) + 3CO₂(g)

Moles of boron carbonate decomposed is 5.0 mol

To find the moles of CO₂ produced we are going to use the mole ratio.

Mole ratio of B₂(CO₃)₃ to CO₂ is 1 : 3

Therefore;

Moles of CO₂ = Moles of B₂(CO₃)₃ × 3

                      = 15 mol

Therefore, 15 moles of CO₂ will be produced

   

4 0
3 years ago
Chem help 36 and 37 the word cut off on 37 is larger​
ad-work [718]

The solution for problem 36 is in the picture attached. I am 80% sure it’s correct.

7 0
3 years ago
Other questions:
  • Name the salt k4[pt(co3)2f2] given that the carbonate ion acts as a monodentate ligand in the complex. the oxidation number of p
    6·2 answers
  • A story on chemical reaction or electric current
    10·2 answers
  • Which of the following examples illustrates a number that is correctly rounded to three significant figures?
    14·1 answer
  • WHat do particles move in a solid by?
    12·2 answers
  • Can somebody answer this please
    15·1 answer
  • Os
    13·1 answer
  • Is water a metal or non metal
    10·2 answers
  • PLEASE HELP QUICK AS POSSIBLE!!!!
    13·1 answer
  • Which object has the greatest velocity? Assume the objects have equal masses.
    13·1 answer
  • How many molecules and atoms in 6 moles of P203?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!