Question

1. A student sees tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drinks. The student squeezes the bottle.
a. The bubbles will shrink, and some may vanish.
b. The bubbles will grow, and more may appear.
c. The bubbles won't change.
2. A student has two unopened 33cL cans containing carbonated water. Can A has been stored in the garage (32°C) and can B has been stored in the fridge (8°C). The student opens one can at the time, both cans make a fizz.
a. Can A will make a louder and stronger fizz than can B.
b. Can B will make a louder and stronger fizz than can A.
c. The fizz will be the same for both cans.
d. There is not enough information to predict which can will make the louder fizz.

Answer 1

Answer:

1) The bubbles will grow, and more may appear.

2)Can A will make a louder and stronger fizz than can B.

Explanation:

When you squeeze the sides of the bottle you increase the pressure pushing on the bubble, making it compress into a smaller space. This decrease in volume causes the bubble to increase in density. When the bubble increases in density, the bubble will grow and more bubbles will appear. Therefore, Changing the pressure (by squeezing the bottle) changes the volume of the bubbles. The number of bubbles doesn't change, just their size increases.

Carbonated drinks tend to lose their fizz at higher temperatures because the loss of carbon dioxide in liquids is increased as temperature is raised. This can be explained by the fact that when carbonated liquids are exposed to high temperatures, the solubility of gases in them is decreased. Hence the solubility of CO2 gas in can A at 32°C is less than the solubility of CO2 in can B at 8°C. Thus can A will tend to make a louder fizz more than can B.