The concentration of ClO₂⁻ at equilibrium if the initial concentration of HClO₂ is 0.0654.
<h3>What is concentration?</h3>
The concentration of any substance is the quantity of that substance in per square of the space or container.
The reaction is
HClO₂ + H₂O <=> H₃O⁺ + ClO₂⁻
The pH is 0.454 M
Ka = [H₃O⁺][ClO₂⁻ ] / [HClO₂]
2. 25 × 10⁻² m = [x][x] / 0.454-x]
2 + 0.011 - 0.004994 = 0
solve the quadratic equation
x = 0.0654 = [H3O+] = [ClO2-]
pH = -log (H3O+)
pH = -log(0.0654)
pH = 1.2
equilibrium concentrations of
[HClO2] = 0.454 -x = 0.454 -0.0654 = 0.3886 M
[ClO2- ] = x = 0.0654
Thus, the equilibrium concentrations is 0.0654.
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Answer:
1.89 nol Cu(NO3)2
Explanation:
if you calculate it it will be 1.89
Hello!
datos:
Molarity = 
ps: The ionization constant of the nitric acid is strong (100% ionized in water) or completely dissociates in water, so the pH will be:
![pH = - log\:[H_3O^+]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5C%3A%5BH_3O%5E%2B%5D%20)
![pH = - log\:[2*10^{-4}]](https://tex.z-dn.net/?f=%20pH%20%3D%20-%20log%5C%3A%5B2%2A10%5E%7B-4%7D%5D%20)
Note:. The pH <7, then we have an acidic solution.
I Hope this helps, greetings ... DexteR!
The equation for carbon-14 emission by Radium-223 nuclei is given below:
<h3>What is radioactivity?</h3>
Radioactivity is the spontaneous decay of a substance with emission of radiation.
The equation for carbon-14 emission by Radium-223 nuclei is given below:
In conclusion, the emission of carbon-14 by Radium-223 nuclei produces Lead-209 nuclei.
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I suspect that the pressure of this change is constant therefore
The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial Change
Initially we have 2L at 20 degress what temperature will be at 1L.
2/20 = 1/T
0.1 = 1/T
0.1T = 1
T = 1/0.1
T = 10 degress celsius.
Hope this helps if you won't be able to understand what is the combined gas law just tell me :).
