Answer:
Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.
Explanation:
From the given,
Mass of sodium carbonate
= 8.85 g
Loss mass
= 1.28 g
Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g


Therefore, the compound has only one water molecule.
Molecular formula of the compound is
an name of the compound is <u>sodium carbonate mono hydrate.</u>
Hence, the type of the compound is Mono hydrate.
Just multiply 9.5 by Avogadro's number. You get 5.72 x 10^24 atoms.
At the very least, an oxoacid must 1) be an acid and 2) contain oxygen.
Ba(OH)2 (barium hydroxide) is a strong base. HCN, HF, and hydrochloric acid (HCl) don't contain oxygen.
Nitrous acid (HNO2) is an acid, and it contains oxygen. And the acidic hydrogen is bonded to an oxygen. Thus, nitrous acid qualifies as an oxoacid.
I don't know if H2PO4 is a typo; if not, then it would properly be written as H2PO4⁻ since it's the first deprotonation product of phosphoric acid, H3PO4. In any case, H2PO4⁻ is still acidic, albeit weakly, and its acidic hydrogens are bonded to the oxygen atoms. Thus, "H2PO4" would qualify as an oxoacid (for that matter, H3PO4 would also be an oxoacid).
Chloric acid (HClO3) is an acid, and it contains oxygen; its acidic hydrogen is bonded to an oxygen atom. Thus, chloric acid qualifies as an oxoacid.
Answer:
The order of reaction is 2.
Rate constant is 0.0328 (M s)⁻¹
Explanation:
The rate of a reaction is inversely proportional to the time taken for the reaction.
As we are decreasing the concentration of the reactant the half life is increasing.
a) For zero order reaction: the half life is directly proportional to initial concentration of reactant
b) for first order reaction: the half life is independent of the initial concentration.
c) higher order reaction: The relation between half life and rate of reaction is:
Rate = ![\frac{1}{k[A_{0}]^{(n-1)}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bk%5BA_%7B0%7D%5D%5E%7B%28n-1%29%7D%7D)
Half life =![K\frac{1}{[A_{0}]^{(n-1)} }](https://tex.z-dn.net/?f=K%5Cfrac%7B1%7D%7B%5BA_%7B0%7D%5D%5E%7B%28n-1%29%7D%20%7D)
![\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }](https://tex.z-dn.net/?f=%5Cfrac%7B%28halflife_%7B1%7D%29%7D%7B%28halflife_%7B2%7D%29%7D%3D%5Cfrac%7B%5BA_%7B2%7D%5D%5E%7B%28n-1%29%7D%7D%7B%5BA_%7B1%7D%5D%5E%7B%28n-1%29%7D%20%7D)
where n = order of reaction
Putting values
![\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}](https://tex.z-dn.net/?f=%5Cfrac%7B109%7D%7B231%7D%3D%5Cfrac%7B%5B0.132%5D%5E%7B%28n-1%29%7D%7D%7B%5B0.280%5D%5E%7B%28n-1%29%7D%7D)

Hence n = 2
![halflife=\frac{1}{k[A_{0}]}](https://tex.z-dn.net/?f=halflife%3D%5Cfrac%7B1%7D%7Bk%5BA_%7B0%7D%5D%7D)
Putting values

K = 0.0328