The roots of the equation x^2+px+q=0 are -1 and 3. what is the value of q?

1 answer:

6 0

Answer:

Step-by-step explanation:

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Sonja [21]

I hope this helps you

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Schach [20]

Answer

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Step-by-step explanation:

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solmaris [256]

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zzz [600]

Answer: See below

Step-by-step explanation:

When you see that something is to the power of a negative number, it is another way of saying 1 over.

$(2x-2)^-^3=\frac{1}{(2x-2)^3} =\frac{1}{(2x-2)(4x^2-8x+4)} =\frac{1}{8x^3-8x^2+8x-8}$

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