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Crazy boy [7]
2 years ago
11

How many electrons are in 11B+3 ?

Chemistry
2 answers:
BARSIC [14]2 years ago
5 0

Answer: 5 electrons

Explanation:

Mark me brainliest.

klemol [59]2 years ago
3 0
5 electrons


The number 11 represents the mass number which is the sum of protons and neutrons. if you look in the periodic table, you will notice that boron has 5 protons. So, it must have 5 electrons because it is a stable element and has no net charge.
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How many moles of silver chloride, produced from 100 g of silver nitrate reacting with barium chloride BaCl2?
Dmitrij [34]

Answer:

Equation of Reaction

2AgNO3 + BaCl2 === 2AgCl + Ba(NO3)2

Molar Mass of AgNO3 = 170g/mol

Moles of reacting AgNO3 = 100g/170gmol-¹

=0.588moles of AgNO3

From the equation of reaction...2moles of AgNO3 reacts to Produce 2Moles of Silver Chloride

So Their ratio is 2:2.

This means that 0.588Moles of AgCl Will be produced too.

ANSWER...0.588MOLES OF AgCl WILL BE PRODUCED.

7 0
3 years ago
Treatment of butanedioic (succinic) anhydride with ammonia at elevated temperature leads to a compound of molecular formula C4H5
artcher [175]

Answer:

The product is Methyl cyanoacetate

Explanation: see structure attached

5 0
2 years ago
Is NaCl CH3OH LiOH or H2SO4 a bronsted acid
vesna_86 [32]

Answer:

D. H₂SO₄

Explanation:

Bronsted acids are those that donate H+ ions. In this question, H₂SO₄ is a Bronsted acid.

Note: H₂SO₄ is one of seven strong acids that you should try to memorize.

3 0
3 years ago
6. A. If 4.50 mols of ethane, C2H6, undergoes combustion according to the unbalanced equation
uranmaximum [27]

Answer:

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Explanation:

i hope it's helpful

6 0
2 years ago
Calculate the ph of the solution made by adding 0.50 mol of hobr and 0.30 mol of kobr to 1.00 l of water. the value of ka for ho
nikdorinn [45]
To fully understand the problem, we use the ICE table to identify the concentration of the species. We calculate as follows:

Ka = 2.0 x 10^-9 = [H+][OBr-] / [HOBr] 

HOBr  = 0.50 M 
KOBr  = 0.30 M = OBr-

<span>     HOBr + H2O <-> H+ + OBr- </span>
<span>I     0.50        -              0          0.30 </span>
<span>C       -x                        x             x 
</span>---------------------------------------------
<span>E(0.50-x)                    x       (0.30+x) </span>

<span>Assuming that the value of  x is small as compared to 0.30 and 0.50 </span>

<span>Ka = 2.0 x 10^-9 = x (0.30) / 0.50) </span>

<span>x = 3.33 x 10^-9 = H+</span>
pH = 8.48
3 0
3 years ago
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