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2 years ago

Is x = 3 a solution to the equation x + 7 = 11?

Mathematics

2 answers:

sineoko [7]2 years ago

7 0

Answer:

The correct answer is A. No, because 3 + 7 = 11 is not true.

Step-by-step explanation:

Just like the answer says, if x =3, then that would mean that 3 + 7 = 11. Since

3 + 7 =10, this statement is not true.

Therefore, the correct answer is A.

Hope this helps! :D

olya-2409 [2.1K]2 years ago

3 0

Answer:

Step-by-step explanation:

3+7 is 10, not 11. Therefore, x cannot be 3.

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julia-pushkina [17]

Answer:

Rewriting $6^{-2}$ without an exponent we get $\mathbf{\frac{1}{36}}$

Step-by-step explanation:

We need to rewrite the following without an exponent. $6^{-2}$

We need to solve the exponent to find the result.

We know the exponent rule: $a^{-b}=\frac{1}{a^b}$

Now using this rule to solve the equation:

$6^{-2}\\=\frac{1}{6^2}\\We \:know \:that\:6^2 = 6\times 6=36\\=\frac{1}{36}$

So, Rewriting $6^{-2}$ without an exponent we get $\mathbf{\frac{1}{36}}$

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Can anyone help me on this? I'm so confused!

DanielleElmas [232]

Answer:

X=9

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Step-by-step explanation:

Hope this helps!! Have an amazing day!!

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2 years ago

Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis

Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line $\overline{AA'}$ as the dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of $\overline{AA'}$ because line $\overline{EG}$ bisects $\overline{AA'}$ .

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3 years ago

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guajiro [1.7K]

Answer:

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