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3 years ago

What do scientists believe formed the moon's craters and regolith

Chemistry

2 answers:

seraphim [82]3 years ago

4 0

Answer:

What is most widely accepted today is the giant-impact theory. It proposes that the Moon formed during a collision between the Earth and another small planet, about the size of Mars. The debris from this impact collected in an orbit around Earth to form the Moon.

Explanation:

Gnoma [55]3 years ago

3 0

Flying asteroids and how it formed

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How many grams of chlorine gas can be produced if 15 grams of FeCl3 reacts with 4 moles of O2? What is the limiting reactant? Wh

Alika [10]

Answer:

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4 years ago

What is the structural formula of pent-3-en-1-yl? <br>Thx

krek1111 [17]

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3 years ago

Lead (II) carbonate decomposes to give lead (II) oxide and carbon dioxide: PbCO 3 (s) PbO (s) CO 2 (g) ________ grams of lead (I

blsea [12.9K]

Answer:

We will have 7.30 grams lead(II) oxide

Explanation:

Step 1: Data given

Mass of lead (II)carbonate = 8.75 grams

Molar mass PbCO3 = 267.21 g/mol

Step 2: The balanced equation

PbCO3 (s) ⇆ PbO(s) + CO2(g)

Step 3: Calculate moles PbCO3

Moles PbCO3 = mass / molar mass

Moles PbCO3 = 8.75 grams / 267.21 g/mol

Moles PbCO3 = 0.0327 moles

Step 4: Calculate moles PbO

For 1 mol PbCO3 we'll have 1 mol PbO and 1 mol CO2

For 0.0327 moles PbCO3 we'll have 0.0327 moles PbO

Step 5: Calculate mass PbO

Mass PbO = moles PbO * molar mass PbO

Mass PbO = 0.0327 moles * 223.2 g/mol

Mass PbO = 7.30 grams

We will have 7.30 grams lead(II) oxide

7 0

4 years ago

[20 Points!] The solubility product constant of calcium hydroxide is 6.5 x 10^-6. If 0.10 mol of sodium hydroxide is added to 1

sleet_krkn [62]

For Ca(OH)2, Ksp = [Ca2+][OH-]^2
You have your Ksp as 6.5 x 10^-6. Your [OH-] comes almost entirely from the 0.10 mol of NaOH, since Ca(OH)2 barely dissolves. Your [OH-] is therefore 0.10 M (since you have 1 L of solution).

6.5 x 10^-6 = [Ca2+](0.10)^2
Solve for [Ca2+]:
6.5 x 10^-6 / (0.10)^2 = [Ca2+]
[Ca2+] = 0.00065 M

The maximum concentration of [Ca2+] is 0.00065 M, and you have 0.0010 M Ca(OH)2, so you’ll end up with 0.00065 M Ca2+ in solution.

8 0

3 years ago

How many molecules of manganese (IV) sulfate are there if you are given 542.32g?

MAVERICK [17]

Answer:

3.47 mol MnSO4

Explanation:

54.94 + 32.07 + (16 × 4) = 151.01g/mol MnSO4

542.32g / 151.01g/mol = 3.47 mol MnSO4

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3 years ago