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3 years ago

Identify the type of question, mg->mg^2+ +2e-

Chemistry

1 answer:

mash [69]3 years ago

7 0

The equation is an oxidation half-reaction, because the Mg is losing electrons to

form Mg²⁺.

Loss of Electrons is Oxidation and

Oxidation Is Loss of electrons.

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B. Determine the percent composition of each element in NaCl. (1 point) Must show work to

andrey2020 [161]

Answer:

Sodium (Na): (.5 point)

22.99+35.453=58.433. 22.99/58.433= 39%

Chlorine (Cl): (.5 point)

22.99+35.453=58.433. 35.453/58.433= 61%

Explanation:

8 0

2 years ago

HELP ME PLEASE ASAP. I'LL MARK YOU BRAINLIEST ITS NUMBER 23.

Ivanshal [37]

Answer:

The answer is A

Explanation:

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2 years ago

How many moles of HCl are present in 0.70 L of a 0.63 M HCl solution?

eimsori [14]

So the molarity equation is moles of solute/liters of solution. so i’m pretty sure the answer should be 0.63/0.70= .9

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2 years ago

Consider X + Z -> ?

Licemer1 [7]

Answer:

Explanation:

Element Z acquires two electrons from element X for stability

4 0

3 years ago

A solution of H 2 SO 4 ( aq ) H2SO4(aq) with a molal concentration of 8.01 m 8.01 m has a density of 1.354 g / mL . 1.354 g/mL.

anzhelika [568]

Answer:

[H₂SO₄] = 6.07 M

Explanation:

Analyse the data given

8.01 m → 8.01 moles of solute in 1kg of solvent.

1.354 g/mL → Solution density

We convert the moles of solute to mass → 8.01 mol . 98g /1mol = 785.4 g

Mass of solvent = 1kg = 1000 g

Mass of solution = 1000g + 785.4 g = 1785.4 g

We apply density to determine the volume of solution

Density = Mass / volume → Volume = mass / density

1785.4 g / 1.354 g/mL = 1318.6 mL

We need this volume in L, in order to reach molarity:

1318.6 mL . 1L / 1000mL = 1.3186 L ≅ 1.32L

Molarity (mol/L) → 8.01 mol / 1.32L = 6.07M

4 0

2 years ago

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