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Sedaia [141]
3 years ago
10

Time that is measured in definite periods such as minutes, day,and years is called

Chemistry
1 answer:
aleksley [76]3 years ago
7 0

Answer:

1. relative time

2.absolute time

Explanation:

Time that is measured in definite periods such as minutes, days, and years is called

a. Relative time.

b. absolute time.

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Without consulting Appendix B, arrange each group in order of increasing standard molar entropy (S°). Explain.(c) SF₆(g), SF₄(g)
Andre45 [30]

The increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

SF₄(g) has lower standard molar entropy. Due to less complexity of this molecules.

While, complexity increases from SF₆(g) to S₂F₁₀(g). Therefore, the standard molar entropy of S₂F₁₀(g) is greater than SF₆(g).

Thus, we concluded that the increasing order of standard molar entropy (S°) is as follow:

SF₄(g) < SF₆(g) < S₂F₁₀(g)

learn more about standard molar entropy:

brainly.com/question/15908262

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7 0
2 years ago
Which scientist was the first to use the telescope in astronomy? Copernicus Newton Kepler Galileo
coldgirl [10]

The scientist that was the first to use the telescope in astronomy was Newton

8 0
3 years ago
An
Pavel [41]
I think it is c but I’m not sure
6 0
3 years ago
Read 2 more answers
An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,
natima [27]

Answer:

The answer is "Option B".

Explanation:

\to CH_3COOH + NaOH \longleftrightarrow  CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\  NaOH = (5 \ E-3\  L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\

\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\  L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\

\to C \ CH_3COONa =  \frac{(0.01\  mol + 5 \ E-4\  mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\

\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\  E-6 - 1.75\  E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to  [H_3O^+] = 1.5835\  E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to  pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7

5 0
3 years ago
Convert 0.965 moles of H2O to grams SHOW WORK
Tasya [4]

Answer:

17.37 grams

Explanation:

mass=moles × molar mass

mass = 0.965 × 18

mass = 17.37g

5 0
3 years ago
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