Answer:
2,54x10² mmHg
Explanation:
To solve this problem you can use Clausius-Clapeyron equation that serves to estimate vapor pressures or temperatures:

Where:
P1 is 1,00x10² mmHg
ΔHvap is 39,3 kJ/mol
R is gas constant 8,314x10⁻³ kJmol⁻¹K⁻¹
T1 is 34,90°C + 273,15 = 308,05 K
T2 is 54,81°C + 273,15 = 327,96 K
Thus:

Thus, P2 is <em>2,54x10² mmHg</em>
I hope it helps!
Answer:
Dark matter is nonluminous material that is postulated to exist in space and that could any of Several form including weakly interacting particles.
Explanation:
dark matter is basically composed of particles that do not absorb, reflect or emit light, so they can't be detected by observing electromagnetic radiation.
Ethylene is the starting material for the preparation of a number of two-carbon compounds including ethanol (industrial alcohol), ethylene oxide (converted to ethylene glycol for antifreeze and polyester fibres and films), acetaldehyde (converted to acetic acid), and vinyl chloride (converted to polyvinyl chloride).
<h2>Diethylether (DTH) andTetrahydrofuran (THF).</h2>
Explanation:
- Grignard reactions reacts with water forming alkanes.
- The water present causes the reagent to decompose rapidly.
- So, the solvents which are utilized in the experimental procedure to minimize exposure of the grignard reagents to air and/ormoisture are solvents such as anhydrous diethyl ether or tetrahydrofuran(THF), poly(tetramethylene ether) glycol (PTMG).
- The reason for the use of these solvents is the oxygen present in these solvents stabilizes the magnesium reagent.
- THF (Tetrahydrofuran) is a stable compound.
Lattice energy of potassium nitrate (KNO3) = -163.8 kcal/mol
Hydration energy of KNO3 = -155.5 kcal/mole
Heat of solution is the amount of heat absorbed by water when 1 mole of KNO3 is dissolved in it
Heat of solution = Hydration energy - Lattice energy
= -155.5 -(-163.8) = 8.3 kcal/mol
1 kcal/mol = 4.184 kJ/mole
Therefore, 8.3 kcal/mole = 4.184 * 8.3 = 34.73 kJ/mol
Now, 34.73 kJ of heat is absorbed when 1 mole of KNO3 is dissolved
The given 105 kJ of heat would correspond to : 105/34.73 = 3.023 moles of KNO3
Molar mass of KNO3 = 101.1 g/mole
Mass of KNO3 = Molar mass * moles
= 101.1 * 3.023 = 305.63 g = 0.3056 kg