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3 years ago

1. organisms of different species that share similar characteristics most likely have..

Chemistry

1 answer:

SSSSS [86.1K]3 years ago

6 0

Answer:

1. Parents from both species.

2. Because of natural selection.

Explanation:

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What happens to the ice on a frozen lake, when the temperature changes? Uhkhub hbi

Nat2105 [25]

When temperature changes it melts the ice over the lake.

As we know the melting point of ice or water is 0°C or 273K
So if the temperature arises up to 0°C or 273.16K then the ice starts melting .

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3 years ago

Which element is classified as an alkali metal? Rb Sr Zr Cl

qwelly [4]

Hi there.

Alkali metals are known as the group 1 elements.

When we know this, we just have to look to group 1 of the periodic table.

Rb (Rubidium) is in group 1; it is classified as an alkali metal.

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3 years ago

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A certain compound is made up of one phosphorus (P) atom, three chlorine (Cl) atoms, and one oxygen (O) atom. What is the chemic

Karolina [17]

POCl3 is the chemical formula of compound.

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3 years ago

How accurate are heist movies where the robbers throw a bunch of gold bars in a bag and carry it out of the bank? Very, because

Oduvanchick [21]

Answer:

Not very, because gold is too heavy to carry many bars at once.

Explanation:

Such movies are far from being accurate.

A standard gold bar weighs about 12.4 kilograms, an equivalence of approximately 27 pounds or 437 ounces, in real life. Hence, a bunch of gold bars would weigh far more than what one person can just lift up, throw, or carry as if it is a bunch of cotton wool.

The correct answer is, therefore, that such movies are far from reality because gold is too heavy to carry many bars at once.

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3 years ago

Octane has a density of 0.692 g/ml at 20oc. how many grams of o2 are required to burn 15.0 gal of c8h18 (the average capacity of

Hatshy [7]

Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

Molar mass of octane = 114g

We know that,

1 gal = 3.78541L = 3785.4ml

Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

C₈H₁₈ + 12.5O₂ ---------> 8CO₂ + 9H₂O

Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

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2 years ago